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Maurinko [17]
3 years ago
10

You can see stars brighter than magnitude +6 with your naked eye under dark sky conditions, and you can also see the full moon a

t magnitude –13. (You can glance at the Sun, which is at magnitude –27, but you can't safely look at the Sun.) Given these limits, what is the dynamic range of the naked eye?
Physics
1 answer:
Mariana [72]3 years ago
6 0
-6 uh 89 0 -+= 62 uwuwhhiwhiuhwiuhwuihhishishoknsk
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Two Earth satellites, A and B, each of mass m = 940 kg , are launched into circular orbits around the Earth's center. Satellite
-Dominant- [34]

Answer:

The required work done is 6.5\times10^{9}\ J

Explanation:

Given that,

Mass of each satellites = 940 kg

Altitude of A = 4500 km

Altitude of B = 11100 km

We need to calculate the potential energy

Using formula of potential

U_{A}=-\dfrac{Gm_{A}m_{E}}{r_{A}}

Put the value into the formula

U_{A}=-\dfrac{6.67\times10^{-11}\times940\times5.98\times10^{24}}{6.38\times10^{6}+4.50\times10^{6}}

U_{A}=-3.44\times10^{10}\ J

We need to calculate the potential energy

Using formula of potential

U_{B}=-\dfrac{Gm_{B}m_{E}}{r_{A}}

Put the value into the formula

U_{B}=-\dfrac{6.67\times10^{-11}\times940\times5.98\times10^{24}}{6.38\times10^{6}+11.10\times10^{6}}

U_{B}=-2.14\times10^{10}\ J

We need to calculate the value of k_{A}

Using formula of k_{A}

k_{A}=-\dfrac{1}{2}U_{A}

Put the value into the formula

k_{A}=\dfrac{1}{2}\times3.44\times10^{10}

k_{A}=1.72\times10^{10}\ J

We need to calculate the value of k_{B}

Using formula of k_{B}

k_{B}=-\dfrac{1}{2}U_{B}

Put the value into the formula

k_{B}=\dfrac{1}{2}\times2.14\times10^{10}

k_{B}=1.07\times10^{10}\ J

We need to calculate the work done

Using formula of work done

W=\Delta K+\Delta U

W=(k_{B}-k_{A})+(U_{B}-U_{A})

W=(-\dfrac{U_{B}}{2}+\dfrac{U_{A}}{2})+(U_{B}-U_{A})

W=\dfrac{1}{2}(U_{B}-U_{A})

Put the value into the formula

W=\dfrac{1}{2}\times(-2.14\times10^{10}+3.44\times10^{10})

W=6.5\times10^{9}\ J

Hence, The required work done is 6.5\times10^{9}\ J

7 0
3 years ago
Which statement is true regarding DC current? A. The electrons move back and forth. B. There can only be one voltage supplied. C
Kazeer [188]

Answer:

B

Explanation:

In a DC current, the current supplied is steady motion (a straight horizontal line in a graph) and this is what makes it had to transform. The alternating current takes a sine wave motion in a graph. This means is voltage varies from zero to peak and reverses polarity. The rate at which it achieves this is its frequency in Hertz.

7 0
3 years ago
Explain a situation in which you can accelerate even though your speed doesn't change
ANTONII [103]
You can accelerate by changing direction, even though you don't speed up/down. Remember that acceleration is a vector so, it has a direction and a magnitude. That's why this works! Hope it helps.
4 0
4 years ago
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What is the momentum of a 5 kg object that has a velocity of 1.2 m/s?
guajiro [1.7K]
In the given question all the required details are given. Using these information's a person can easily find the momentum of the object. In the question it is already given that the mass of the object is 5 kg and the velocity at which it is traveling is 1.2 m/s.
We know the equation of finding momentum as
Momentum = mass * velocity
                   = 5 * 1.2
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So the momentum of the object is 6 Newton.
8 0
3 years ago
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The courtroom role that possesses the most discretion is?
KonstantinChe [14]
The role of the Prosecutor's
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