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Rainbow [258]
3 years ago
13

Which of these is true about an object thrown straight up in the absence of air resistance? Its acceleration increases as it fal

ls. Its acceleration and velocity are both momentarily zero at maximum height. Its acceleration is constant. The direction of its velocity is constant.
Physics
1 answer:
Taya2010 [7]3 years ago
8 0
Its acceleration is constant . . . 9.8 M/s-squared downward. That's the acceleration of gravity on Earth.
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What is the definition of the half-life of a radioactive isotope?
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Answer:Half-life is the amount of time it takes for the initial mass of the isotope to decompose, by half, into other lighter atoms.

Explanation:Different radioactive isotopes have different half-lives. For example, the element technetium-99m has a half life of 6 hours. This means that is 100 kg of the element is left to decay, in 6 hours, 50kg of the mass will have changed into other elements/atoms. The half-life of uranium-238 is 4.5 billion years while that of polonium-216 is only 0.145 seconds.

5 0
3 years ago
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A body 'A' of mass 1.5kg travelling along the positive X-axis with speed of 4.5m/s collides with another body 'B' of mass 3.2kg,
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I already answered this question. 
Please refer to this link brainly.com/question/8743596.
6 0
3 years ago
A person lifts a 25 kg box of old sports equipment at an angle of 75 degrees to the vertical to a shelf 2.6 meters above. How mu
kogti [31]

Answer:

164.87 J

Explanation:

From the question,

Work done (W) = mghcosθ........................ Equation 1

Where m = mass of the box, h = height, g = acceleration due to gravity, θ = angle to the vertical

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Substitute these value into equation 1

W = 25×9.8×2.6×cos75°

W = 164.87 J.

6 0
3 years ago
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sveticcg [70]

the answer is false

7 0
3 years ago
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A boxer punches a sheet of paper in mid air, and brings it from rest up to a speed of 25 m/s in 0.05 s. if the mass of the paper
zepelin [54]
Ok, so you've got to figure out a force F and you have the speed in which the boxer punches on determinate time and the mass of the sheet of paper.

So based on the formula that says that the Force is equal to the mass multiplied by the acceleration => F=ma.
You look at it and see that you only have mass which is measured on KG so there is no problem.
then you have the acceleration which is measured on meters and is defined by: a = Δv/Δt 
So now you can replace the velocity and the time you have there
⇒ a 25m/s / 0.05s 
you have computing that ⇒ 50m because the seconds were cancelled out.
and then you plug the meters into the force equation.
F=(0.005kg)(50)
F=0.25N
so the boxer will have a force of 0.25 Newton's.

6 0
3 years ago
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