Is a 15 year old sophomore considered part of the labor force? Why or why not?

8. The time period of artificial satellite in a circular orbit of radius R is T. The radius of the orbit in which time period is

Elena-2011 [213]

Explanation:

It is given that,

The time period of artificial satellite in a circular orbit of radius R is T. The relation between the time period and the radius is given by :

$T^2\propto R^3$

The radius of the orbit in which time period is 8T is R'. So, the relation is given by :

$(\dfrac{T}{T'})^2=(\dfrac{R}{R'})^3$

$(\dfrac{T}{8T})^2=(\dfrac{R}{R'})^3$

$\dfrac{1}{64}=(\dfrac{R}{R'})^3$

$R'=4\times R$

So, the radius of the orbit in which time period is 8T is 4R. Hence, this is the required solution.

4 0

3 years ago

Which of the following corresponds to an alpha particle?

andrey2020 [161]

Answer:

Atomic number=No. of protons=No. of electrons in ground state(unchanged atom)

Atomic number=13=No. of protons

Atomic mass=no. of protons+no. of neutrons=13+14=27

For isotope no. of proton=13(same atomic number but different mass number are isotopes)

no. of electrons=13

no. of neutrons=14+2=16

Explanation:

hope it's help you

4 0

3 years ago

When preparing the diazonium salt, the solution is tested with potassium iodide-starch paper. a positive test is the immediate f

Dahasolnce [82]

KI-starch paper allows the detection of strong oxidizers such as nitrite. It is used here to control diazotization of 4-nitroaniline. Nitrite oxidizes potassium iodide in order to form elemental iodine which reacts with starch to a blue-violet complex. With KI-starch paper, enough sodium nitrite is added to produce nitrous acid, which <span>then will react with 4-nitroaniline to form a diazonium salt.</span>

8 0

3 years ago

If u answer this correctly I’ll mark you brainliest

olga2289 [7]

Answer:

6 is the right answer I know cause I like science

4 0

3 years ago

Read 2 more answers

Consider the following intermediate chemical equations.

QveST [7]

Answer: 250 kJ

Explanation: According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

$P_4(s)+6Cl_2\rightarrow 4PCl_3$ $\Delta H_1=-2439kJ$ (1)