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3 years ago

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Given two temperatures, 36 °F and 72 °F, which of the following correctly compares the number of opportunities for particles to

align during a chemical reaction?
Same at both
Greater at 36 °F
Greater at 72 °F
Does not depend on temperature

1 answer:

Liono4ka [1.6K]3 years ago

5 0

The correct answer is "Greater at 72 °F " hope it helps

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Iron(III) oxide and hydrogen react to form iron and water, like this: (s)(g)(s)(g) At a certain temperature, a chemist finds tha

stepan [7]

The question is incomplete, here is the complete question:

Iron(III) oxide and hydrogen react to form iron and water, like this:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

At a certain temperature, a chemist finds that a 5.4 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, iron, and water at equilibrium has the following composition:

Compound Amount

$Fe_2O_3$ 3.54 g

$H_2$ 3.63 g

Fe 2.37 g

$H_2O$ 2.13 g

Calculate the value of the equilibrium constant for this reaction. Round your answer to 2 significant digits

<u>Answer:</u> The value of equilibrium constant for the given reaction is $2.8\times 10^{-4}$

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

<u>For hydrogen gas:</u>

Given mass of hydrogen gas = 3.63 g

Molar mass of hydrogen gas = 2 g/mol

Volume of solution = 5.4 L

Putting values in above equation, we get:

$\text{Molarity of hydrogen gas}=\frac{3.63}{2\times 5.4}\\\\\text{Molarity of hydrogen gas}=0.336M$

<u>For water:</u>

Given mass of water = 2.13 g

Molar mass of water = 18 g/mol

Volume of solution = 5.4 L

Putting values in above equation, we get:

$\text{Molarity of water}=\frac{2.13}{18\times 5.4}\\\\\text{Molarity of water}=0.0219M$

The given chemical equation follows:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[H_2O]^3}{[H_2]^3}$

The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression. So, the concentration of iron and iron (III) oxide is not present in equilibrium constant expression.

Putting values in above equation, we get:

$K_c=\frac{(0.0219)^3}{(0.336)^3}\\\\K_c=2.77\times 10^{-4}$

Hence, the value of equilibrium constant for the given reaction is $2.8\times 10^{-4}$

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3 years ago

Plz answer this fast... will mark ur answer as brainliest

Xelga [282]

Answer:

When fuels are incompletely burnt, they release carbon monoxide gas into the atmosphere. This gas is very dangerous as it is poisonous in nature

Explanation:

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3 years ago

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How many moles of ammonia are in 735. mL of a 4.25 M aqueous ammonia solution?

zysi [14]

Answer:

*moles = molarity(M=moles/L) * volume (L)

so, you have 4.25 * 0.735 moles

*NH3

* M=n/v

*To determine the number of significant figures in a number use the following 3 rules: Non-zero digits are always significant. Any zeros between two significant digits are significant. A final zero or trailing zeros in the decimal portion ONLY are significant.

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3 years ago

if .40 L if water is added to the volume of cup 3, what would be the new molarity of a 2 M solution of kool-aid

stiks02 [169]

Answer:

0.7692 M ≅ 0.77 M.

Explanation:

It is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.

It can be expressed as:

<em>(MV) before dilution = (MV) after dilution.</em>

M before dilution = 2.0 M, V before dilution = 0.25 L.

M after dilution = ??? M, V after dilution = 0.25 L + 0.40 L = 0.65 L.

∴<em> M after dilution = (MV) before dilution/(V) after dilution</em> = (2.0 M)(0.25 L)/(0.65 L) =<em> 0.7692 M ≅ 0.77 M.</em>

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Answer:

it's not human

Explanation:

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