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bearhunter [10]
3 years ago
14

Evaluate -x+4 when x = -2

Mathematics
2 answers:
musickatia [10]3 years ago
8 0

Answer:

<h2>6</h2>

Step-by-step explanation:

f(x)=-x+4

f(-2)=-(-2)+4

f(-2)=+2+4

f(-2)=6

Hatshy [7]3 years ago
8 0

Answer:

6

Step-by-step explanation:

-(-2)+4=___

+(+2)+4=6

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Which inequality represents a number n that is less than or equal to 3 but greater than -2?
Kisachek [45]
-2 < n \leq 3

This inequality basically says "-2 is less than n, which is less than or equal to 3".

Mark as brainliest if this helped! :)
5 0
3 years ago
Help!!!!! Solve the distance??
hram777 [196]

Answer:

531.4

Step-by-step explanation:

ED/AE=BC/AB

ED=AE*BC/AB

ED=240*620/280

ED=531.4

6 0
3 years ago
Which of the following coordinates represents a point that is collinear with the given points.
charle [14.2K]

Answer:

A) (-4,-1)

Step-by-step explanation:

a line graphed with those coordinates would have a slope of -3/12, or -1/4.

Following that slope, you would go through (-4,-1).  So that is the point collinear with the given points.

8 0
3 years ago
Read 2 more answers
Find the distance between each pair of points. Round your answer to the nearest tenth, if necessary. Hint: Use the Pythagorean T
Paul [167]

The distance between two points on the plane is given by the formula below

\begin{gathered} A=(x_1,y_1),B=(x_2,y_2) \\ \Rightarrow d(A,B)=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2} \end{gathered}

Therefore, in our case,

A=(-1,-3),B=(5,2)

Thus,

\begin{gathered} \Rightarrow d(A,B)=\sqrt[]{(-1-5)^2+(-3-2)^2}=\sqrt[]{6^2+5^2}=\sqrt[]{36+25}=\sqrt[]{61} \\ \Rightarrow d(A,B)=\sqrt[]{61} \end{gathered}

Therefore, the answer is sqrt(61)

In general,

-(-n)=n

Remember that

-n=(-1)\cdot n

Therefore,

\begin{gathered} a-(-n)=a+(-1)(-n)=a+(-1)(-1\cdot n)=a+(-1)^2\cdot n=a+1\cdot n=a+n \\ \Rightarrow a-(-n)=a+n \end{gathered}

6 0
2 years ago
The co-ordinate of point P is (x+3) and Q is (x-3). Then find d(P,Q). If coordinate of R is (x+2). Find d(Q,R).
kari74 [83]

Answer:

<h2>d(P, Q) = 6</h2><h2>d(Q, R) = 5</h2>

Step-by-step explanation:

The formula of a distance between two points A(a) and B(b):

<h3>d = |b - a|</h3>

We have P(x + 3), Q(x- 3), R(x + 2).

Substitute:

d(P, Q) = |(x - 3) - (x + 3)| = |x - 3 - x - 3| = |-6| = 6

d(Q, R) = |(x + 2) - (x - 3)| = |x + 2 - x - (-3)| = |2 + 3| = |5| = 5

5 0
3 years ago
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