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bixtya [17]
3 years ago
8

URGENT PLEASE HELP‼️‼️

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
7 0

Answer:

im sorry this looks difficult

my homework is the same

Step-by-step explanation:

You might be interested in
4
Ira Lisetskai [31]

Answer:

∠MLP = 72° ,           ∠LJK = 22° ,            ∠JKL = 72° ,          ∠KLJ  =  86°

Step-by-step explanation:

Here, given In ΔJLK and  ΔMLP

Here,  JK  II  ML,  LM = MP

∠JLM = 22° and  ∠LMP = 36°

Now, As angles opposite to equal sides are equal.

⇒ ∠MLP = ∠MPL  = x°

Now, in  ΔMLP

By <u>ANGLE SUM PROPERTY</u>:   ∠MLP + ∠MPL  + ∠LMP = 180°

⇒ x° + x° + 36° = 180°

⇒ 2 x  = 180 - 36 = 144

or, x  = 72°

⇒ ∠MLP = ∠MPL  = 72°

Now,as  JK  II  ML

⇒ ∠LJK = ∠JLM = 22° ( Alternate pair of angles)

Now, by the measure of straight angle:

∠MLP + ∠JLM + ∠JLK = 180°  ( Straight angle)

⇒ 72° + 22° + ∠JLK = 180°

or, ∠JLK  =  86°

In , in  ΔJLK

By <u>ANGLE SUM PROPERTY</u>:   ∠JKL + ∠JLK  + ∠LJK = 180°

⇒  ∠JKL + 86° + 22° = 180°

⇒ ∠JKL   = 180 - 108 = 72 , or ∠JKL = 72°

Hence, from  above proof ,  ∠MLP = 72° , ∠LJK = 22° , ∠JKL = 72° ,

∠KLJ  =  86°

7 0
3 years ago
Label each pair of triangles with the postulate or theorem that proves the triangles are congruent.
Annette [7]

Answer:

<u>Δ MNO ≅ Δ PQR by ASA postulate</u>

Step-by-step explanation:

Δ MNO and Δ PQR are congruents because:

1. Their included sides MN and PR are equal (22 units = 22 units)

2. Their angles ∠M and ∠P are equal  (100° = 100°)

3. Their angles ∠N and ∠Q are equal  (35° = 35°)

<u>Now, we can conclude that Δ MNO ≅ Δ PQR by ASA postulate.</u>

4 0
3 years ago
More than three-quarters of the nation’s colleges and universities now offer online classes, and about 23% of college graduates
RUDIKE [14]

Answer:

0.1997 or 19.97%

Step-by-step explanation:

Have taken course online (H) = 23%

Have NOT taken course online (N) = 77%

Have taken course online and don't believe they provide same value (H&D) = 61%

Have NOT taken course online and don't believe they provide same value (N&D) = 73%

The probability that a student has taken a course online given that she does not believe that online courses provide the same educational value as one taken in person is;

P(H|D)=\frac{P(H)*P(H\&D)}{P(H)*P(H\&D)+P(N)*P(N\&D)}\\P(H|D)=\frac{0.23*0.61}{0.23*0.61+0.77*0.73}\\P(H|D)=0.1997

There is a 0.1997 or 19.97% chance that she has taken an online course before.

3 0
4 years ago
Subtract: (3x^2 − 8x + 3) − (−5x^2 + 4x − 5)
koban [17]

Answer:

A

Step-by-step explanation:

Add 3x^2 and 5x^2 now it = 8x^2

Add -8x and -4x = -12x

look at your answer choices the only one that has 8x^2-12x is A

6 0
4 years ago
Read 2 more answers
Sandy paid $27 for her new sweater. If the
RUDIKE [14]

Answer:

36$

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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