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ratelena [41]
3 years ago
15

What is the mathematical equation used when solving calorimetry problems? What does each variable in the equation represent?

Chemistry
1 answer:
liubo4ka [24]3 years ago
7 0

Answer : The mathematical equation used when solving calorimetry problems is:

q=m\times c\times \Delta T}

Explanation :

Calorimetry : It is determining the changes in the energy of a system by measuring the heat transferred with surroundings.

Formula used :

q=m\times c\times \Delta T}

where,

c = specific heat capacity  of calorimeter

m = mass of a substance

q = heat required

\Delta T = change in temperature of substance

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I have 345mL of a 1.5M NaCl solution. If I boil the water until the volume of the solution is 250mL, what will the molarity of t
Karo-lina-s [1.5K]
Answer is
C. 2.07 M


For explanation

M1V1 = M2V2

M2 = (M1V1)/V2

M2 = (1.5M x 345ml) / 250 ml

:. M2 = 2.07 M
8 0
3 years ago
How many grams are in a 1.48x107 ig
Firdavs [7]

Answer:978989989.1429323

Explanation:

6 0
3 years ago
What can be deduced from the fact that a substance has a pH of 7?
balandron [24]

Answer:

A.

Explanation:

A) The number of H+ ions in the substance is equal to the number of OH-ions.

8 0
4 years ago
A 1.85 kg textbook is sitting on a bookshelf 2.23 m above the floor. How much potential energy does it have?
neonofarm [45]

Answer:

\boxed {\boxed {\sf 40.4299 \ Joules}}

Explanation:

Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.

PE= m \times g \times h

The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.

  • m= 1.85 kg
  • g= 9.8 m/s²
  • h= 2.23 m

Substitute the values into the formula.

PE = 1.85 \ kg \times 9.8 \ m/s^2 \times 2.23 \ m

Multiply the first 2 numbers together.

PE=18.13 \ kg*m/s^2 *2.23 \ m

Multiply again.

PE= 40.4299 \ kg*m^2/s^2

  • 1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J)
  • Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J

PE= 40.4299 \ J

The textbook has <u>40.4299 Joules of potential energy.</u>

7 0
3 years ago
In uncompetitive inhibition, the inhibitor can bind to the enzyme only after the substrate binds first. (T/F)
Veronika [31]

Answer:

True

Explanation:

In an uncompetitive inhibition, initially the substrate [S] binds to the active site of the enzyme [E] and forms an enzyme-substrate activated complex [ES].

The inhibitor molecule then binds to the enzyme- substrate complex [ES], resulting in the formation of [ESI] complex, thereby inhibiting the reaction.

This inhibition is called uncompetitive because the inhibitor does not compete with the substrate to bind on the active site of the enzyme.

Therefore, in an uncompetitive inhibition, the inhibitor molecule can not bind on the active site of the enzyme directly. The inhibitor can only bind to the enzyme-substrate complex formed.

       

4 0
3 years ago
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