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3 years ago

If you had a beaker full of black powder which of the following could you have?

2 answers:

8 0

A beaker of black powder can be a mixture with different substances (i.e gunpowder: a mixture of sulfur, charcoal, etc.), an element which can probably be carbon (known as black), and a compound as well which can be potassium nitrate. Hence, the answer is D.

kolbaska11 [484]3 years ago

4 0

Answer:

a. mixture

Explanation:

A black powder probably represents a mixture of several dark colored elements, or several elements that reacted and formed a black colored mixture.

Mixture is the union of two or more different substances (regardless of whether they are simple or compound). It has different and variable (non-fixed) physical characteristics (melting point, boiling point, density, toughness, etc.) compared to its constituent substances.

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Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th

mario62 [17]

Answer: The freezing point of solution is 2.6°C

Explanation:

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

where,

$\Delta T_f$ = $\text{Freezing point of pure solution}-\text{Freezing point of solution}$

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point depression constant = 5.12 K/m = 5.12 °C/m

$m_{solute}$ = Given mass of solute (anthracene) = 7.99 g

$M_{solute}$ = Molar mass of solute (anthracene) = 178.23 g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

$5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC$

Hence, the freezing point of solution is 2.6°C

8 0

2 years ago

How many O2 molecules react with 47 CH4 molecules according to the preceding equation CH4 + O2 → CO2 + H2O

natka813 [3]

I think 93.71 mol.
You need to use stochio

8 0

3 years ago

What is heating and cooling

melisa1 [442]

make or become hot or warm is heating.

cooling is to become colder or cool down from a higher temp.

6 0

3 years ago

It is found that doubling the concentration of a quadruples the reaction rate and tripling the concentration of b triples the re

MatroZZZ [7]

Reactant A must be second order and reactant B first order. Overall = add them so 3rd order.

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3 years ago

suppose you want to treat if a sample compound is ionic. you have these materials: the solid compound, a glass container, a spoo

xz_007 [3.2K]

An ionic compound is a substance that contains atoms that are bonded together through an ionic bond, where electrons are transferred from one atom to another. For the given experiment above, the material that is missing from the list is WATER or solvent. It is necessary because conduction through water will help you identify if a sample compound is ionic through its electrolytes. Ionic compounds that are soluble are typically electrolytes

6 0

2 years ago

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