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mel-nik [20]
3 years ago
7

If you had a beaker full of black powder which of the following could you have?

Chemistry
2 answers:
Evgesh-ka [11]3 years ago
8 0
A beaker of black powder can be a mixture with different substances (i.e gunpowder: a mixture of sulfur, charcoal, etc.), an element which can probably be carbon (known as black), and a compound as well which can be potassium nitrate. Hence, the answer is D. 
kolbaska11 [484]3 years ago
4 0

Answer:

a. mixture

Explanation:

A black powder probably represents a mixture of several dark colored elements, or several elements that reacted and formed a black colored mixture.

Mixture is the union of two or more different substances (regardless of whether they are simple or compound). It has different and variable (non-fixed) physical characteristics (melting point, boiling point, density, toughness, etc.) compared to its constituent substances.

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After 42 days a 2.0 g sample of phosphorus-32 contains only 0.25 g of the isotope. What is the half-life of phosphorus-32?
bija089 [108]
2.0 g 1.0g 0.5g 0.25g
3 and a half lives = 42 days
7 0
3 years ago
Vinegar contains 5g of acetic in 100mL of solution so the (w/v)% concentration is:
Andreyy89

The (w/v)% concentration of vinegar contains 5g of acetic in 100mL of solution is approx 0.5 %

<h3>What is Concentration ?</h3>

The concentration of a chemical substance expresses the amount of a substance present in a mixture.

There are many different ways to express concentration.(w/v)% is one of them.

Given ;

  • Mass of solute(acetic acid) is 5.0 g
  • Volume of solution is 100.0 mL.

We need to convert the grams of acetic acid to moles ;

Formula of acetic acid is CH₃COOH

Thus,

Molar mass of acetic acid = 2(12.01) + 4(1.01) + 2(16)  

                                           = 24.02 + 4.04 + 32

                                           = 60.06 grams per mol

Moles of acetic acid = 5.0/60.06

                                 

                                 = 0.083 moles

(w/v)% = 0.083 x 60 / 1000 x 100

          = 0.498 %

          = 0.5 %

Hence, The (w/v)% concentration of vinegar contains 5g of acetic in 100mL of solution is approx 0.5 %

Learn more about weight percentage here ;

brainly.com/question/22575652

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8 0
2 years ago
Four people are needed to lift a TV set with a single fixed pulley. How many people will be needed to lift the same TV set with
expeople1 [14]
If they need 4 people to a pulley then they would need a 8 to two pulleys
here is the equation
4people*2/pulley*2
8people/2pulley

4 0
4 years ago
Write the precipitation reaction for cobalt(II) hydroxide in aqueous solution: Be sure to specify the state of each reactant and
Len [333]

Answer:

The equation for the precipitation reaction of cobalt (ii) hydroxide is given below:

CoSO₄ (aq) + NaOH (aq) ----> Co(OH)₂ (s) + Na₂SO₄ (aq)

Explanation:

Cobalt (ii) hydroxide is an inorganic compound consisting of cobalt (ii) ions, Co²+ and hydroxide ions, OH-. It is insoluble in water and the pure form known as the beta form is a pink-coloured solid. The impure form which incorporates other anions in its molecular structure is blue in colour and is ustable.

Cobalt (ii) hydroxide is formed as precipitate when an alkaline metallic hydroxide such as sodium hydroxide is mixed with an aqueous cobalt (ii) salt such as cobalt (ii) sulfate. The equation for the precipitation reaction of cobalt (ii) hydroxide is given below:

CoSO₄ (aq) + NaOH (aq) ----> Co(OH)₂ (s) + Na₂SO₄ (aq)

Being a basic hydroxide, cobalt (ii) hydroxide neutralizes acids to form cobalt (ii) salts and water. For example: Co(OH)₂ (s) + H₂SO₄ (aq) ---> CoSO₄ (aq) + H₂O

Thus, cobalt (ii) hydroxide is soluble in acids.

Cobalt(II) hydroxide is used mostly as a drying agent for paints, varnishes, and inks. It is also useful in the preparation of other cobalt compounds.

7 0
3 years ago
What stressors will affect the value for Keq according to Le Chatelier's principle?
Goshia [24]
Le Chatelier's principle describes what happens to a system when something momentarily takes it away from equilibrium. If more reactant is added, the equation will shift to the right in order to make more product. If the temperature is decreased, the reaction will shift to the right to create more heat if it is exothermic (which will increase the product), and to the left if it is endothermic (which will decrease the products). <span> If the pressure is decreased, it will shift in the direction where there are more moles of gas present, because it can now take up more space.</span>
3 0
3 years ago
Read 2 more answers
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