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mel-nik [20]
3 years ago
7

If you had a beaker full of black powder which of the following could you have?

Chemistry
2 answers:
Evgesh-ka [11]3 years ago
8 0
A beaker of black powder can be a mixture with different substances (i.e gunpowder: a mixture of sulfur, charcoal, etc.), an element which can probably be carbon (known as black), and a compound as well which can be potassium nitrate. Hence, the answer is D. 
kolbaska11 [484]3 years ago
4 0

Answer:

a. mixture

Explanation:

A black powder probably represents a mixture of several dark colored elements, or several elements that reacted and formed a black colored mixture.

Mixture is the union of two or more different substances (regardless of whether they are simple or compound). It has different and variable (non-fixed) physical characteristics (melting point, boiling point, density, toughness, etc.) compared to its constituent substances.

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The nucleus of a lead atom has a charge of 82 protons what are the drection and magnitude
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Answer:

left

Explanation:

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Which of the following is a property of water a. polar molecule b. regulates temperature c.universal solvent d. all of the above
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The answer is the letter c
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Read 2 more answers
Which is the Net Ionic Equation for:
arlik [135]

Answer: 2Fe^{3+}(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+2Fe(s)

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and are present in an aqueous state and represented in the form of ions.

Net ionic equation : In the net ionic equations, we do not not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

 The complete balanced ionic equation will be:

2Fe^{3+}(aq)+6Cl^-(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+6Cl^-(aq)+2Fe(s)

 In this equation, Cl^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be:

2Fe^{3+}(aq)+3Mg(s)\rightarrow 3Mg^{2+}(aq)+2Fe(s)

3 0
3 years ago
If an object loses mass, what will happen to its weight?
NeX [460]
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8 0
3 years ago
How many grams would 1.00 billion atoms of sulfur weigh
Zielflug [23.3K]

Answer:

m_S=5.31x10^{-14}gS

Explanation:

Hello,

In this case, by knowing that we have 1 billion ( 1,000,000,000) of atoms of sulfur, via the Avogadro's number we can firstly compute the moles:

n_S=1,000,000,000atoms*\frac{1mol}{6.022x10^{23}atoms}\\\\ n_S=1.66x10^{-15}molS

Then, by using the atomic mass of sulfur (32 g/mol), we can finally compute the mass:

m_S=1.66x10^{-15}molS*\frac{32gS}{1molS}\\ \\m_S=5.31x10^{-14}gS

Best regards.

7 0
3 years ago
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