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mel-nik [20]
3 years ago
7

If you had a beaker full of black powder which of the following could you have?

Chemistry
2 answers:
Evgesh-ka [11]3 years ago
8 0
A beaker of black powder can be a mixture with different substances (i.e gunpowder: a mixture of sulfur, charcoal, etc.), an element which can probably be carbon (known as black), and a compound as well which can be potassium nitrate. Hence, the answer is D. 
kolbaska11 [484]3 years ago
4 0

Answer:

a. mixture

Explanation:

A black powder probably represents a mixture of several dark colored elements, or several elements that reacted and formed a black colored mixture.

Mixture is the union of two or more different substances (regardless of whether they are simple or compound). It has different and variable (non-fixed) physical characteristics (melting point, boiling point, density, toughness, etc.) compared to its constituent substances.

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Determine the percent yield of a reaction that produces 28.65 g of Fe when 50.00 g of Fe2O3 react with excess Al according to th
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The percent yield of the reaction is 82%

Explanation:

First step: make the chemist equation.

2 Al (s) + Fe2O3 (s) → 2 Fe (s) + Al2O3 (s)

As the statement says that aluminun is in excess, the limiting reactant is the Fe2O3

Second step: Find out the moles in the reactant.

Molar weight Fe2O3: 159.7 g/m

Mass / Molar weight = moles

50 g /159.7 g/m = 0.313 moles

Third step: Analyse the reaction. 1 mol of Fe2O3 makes 2 moles of Fe.

1 mol Fe2O3 ____ 2Fe

0.313 mol Fe2O3 ____ 0.626 moles

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Moles . molar weight = mass

55.85g/m . 0.626m = 34.9 grams

This will be the 100% yield of the reaction but we only made 28.65 g

34.9 g ____ 100%

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3 0
3 years ago
Read 2 more answers
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