in a fatty acid, the hydrogen atoms are of the double bond, which produces a kink in the carbon chain. in a fatty acid, the hydr
1 answer:
In a CIS fatty acid, the hydrogen atoms are ON THE SAME SIDE of the double bond, which produces a kink in the carbon chain.
In a TRANS fatty acid, the hydrogen atoms are ON OPPOSITE SIDE of the double bond, which gives a carbon chain without any kink.
In unsaturated fatty acids (with one or more double bonds between carbon atoms), the cis double bonds cause the carbon chain to bend (kink), which gives the molecules an irregular shape (see the picture below).
Cis fatty acids are not as close as trans fatty acids, so they have fewer dispersion forces between their carbon chains.
Cis fatty acids have lower melting and boiling points than trans fatty acids.
More about cis and trans isomers: brainly.com/question/10407072
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This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.
In this case, it is recommended to write the enthalpy for each substance as follows:
Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and and
are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:
It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:
Finally we convert this result to kJ:
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