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Step2247 [10]
1 year ago
13

in a fatty acid, the hydrogen atoms are of the double bond, which produces a kink in the carbon chain. in a fatty acid, the hydr

ogen atoms are of the double bond, which gives a carbon chain without any kink.
Chemistry
1 answer:
crimeas [40]1 year ago
4 0

In a CIS fatty acid, the hydrogen atoms are ON THE SAME SIDE of the double bond, which produces a kink in the carbon chain.

In a TRANS fatty acid, the hydrogen atoms are ON OPPOSITE SIDE of the double bond, which gives a carbon chain without any kink.

In unsaturated fatty acids (with one or more double bonds between carbon atoms), the cis double bonds cause the carbon chain to bend (kink), which gives the molecules an irregular shape (see the picture below).

Cis fatty acids are not as close as trans fatty acids, so they have fewer dispersion forces between their carbon chains.

Cis fatty acids have lower melting and boiling points than trans fatty acids.

More about cis and trans isomers: brainly.com/question/10407072

#SPJ4

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3 years ago
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Answer:

T_F=77.4\°C

Explanation:

Hello there!

In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:

Q_1=-Q_2

In terms of mass, specific heat and temperature change is:

m_1C_1(T_F-T_1)=-m_2C_2(T_F-T_2)

Now, solve for the final temperature, as follows:

T_F=\frac{m_1C_1T_1+m_2C_2T_2}{m_1C_1+m_2C_2}

Then, plug in the masses, specific heat and temperatures to obtain:

T_F=\frac{760g*0.87\frac{J}{g\°C} *52.2\°C+70.7g*3.071\frac{J}{g\°C}*154\°C}{760g*0.87\frac{J}{g\°C} +70.7g*3.071\frac{J}{g\°C}} \\\\T_F=77.4\°C

Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.

Regards!

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