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Step2247 [10]
1 year ago
13

in a fatty acid, the hydrogen atoms are of the double bond, which produces a kink in the carbon chain. in a fatty acid, the hydr

ogen atoms are of the double bond, which gives a carbon chain without any kink.
Chemistry
1 answer:
crimeas [40]1 year ago
4 0

In a CIS fatty acid, the hydrogen atoms are ON THE SAME SIDE of the double bond, which produces a kink in the carbon chain.

In a TRANS fatty acid, the hydrogen atoms are ON OPPOSITE SIDE of the double bond, which gives a carbon chain without any kink.

In unsaturated fatty acids (with one or more double bonds between carbon atoms), the cis double bonds cause the carbon chain to bend (kink), which gives the molecules an irregular shape (see the picture below).

Cis fatty acids are not as close as trans fatty acids, so they have fewer dispersion forces between their carbon chains.

Cis fatty acids have lower melting and boiling points than trans fatty acids.

More about cis and trans isomers: brainly.com/question/10407072

#SPJ4

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3 years ago
200.00 grams of an organic compound is known to contain 83.884 grams of carbon, 10.486
ololo11 [35]

The empirical formula of a given compound is C6H9ON5.

<u>Explanation</u>:

Step 1: Obtain the mass of each element present in grams

                  Element % = mass in g = m

Carbon = 83.884 grams, Hydrogen = 10.486 grams, Oxygen = 18.640 grams, Nitrogen = 86.99 grams.

Step 2: Determine the number of moles of each type of atom present

                m/atomic mass = Molar amount (M)

Molar amount of carbon = (83.884 1 mol ) / 12 g = 6.99

Molar amount of hydrogen = (10.486  1 mol) / 1 g = 10.49

Molar amount of oxygen = (18.64  1 mol) / 16 g = 1.17

Molar amount of nitrogen = (86.99  1 mol) / 14 g = 6.21

Step 3: Divide the number of moles of each element by the smallest number of moles

            M / least M value = Atomic Ratio (R)

Atomic radius of carbon = 6.99 / 1.17 = 5.9 = 6

Atomic radius of hydrogen = 10.49 / 1.17 = 8.9 = 9

Atomic radius of oxygen = 1.17 / 1.17 = 1

Atomic radius of nitrogen = 6.21 / 1.17 = 5

Step 4: Convert numbers to whole numbers. This set of whole numbers are the subscripts in the empirical formula.

            R * whole number = Empirical Formula

The empirical formula of a given compound is C6H9ON5.

7 0
3 years ago
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