1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fgiga [73]
3 years ago
13

Overnight a thin layer of ice forms on the surface of a 40-ft-wide river that is essentially of rectangular cross-sectional shap

e. Under these conditions, the flow depth is 3 ft. During the following day the sun melts the ice cover. Determine the new depth if the flowrate remains the same and the surface roughness of the ice is essentially the same as that for the bottom and sides of the river.
Physics
1 answer:
Arisa [49]3 years ago
3 0

Answer:

the new depth is 2.3 ft

Explanation:

the solution is in the attached Word file

Download docx
You might be interested in
0.8<br> How do convert this into a fraction
Umnica [9.8K]

Answer:

8/10 or 4/5

Explanation:

0.8 out of 1.0

4 0
4 years ago
A football quarterback runs 13 m straight down the playing field in 2.2 s (in the positive direction). He is then hit and pushed
Citrus2011 [14]

[Error 209] Answer could not be seen please reload.

8 0
3 years ago
A women who normally weighs 400 N stands on top of a ladder so high she is one full additional earth radius above the surface of
AveGali [126]

The woman weighs 100N now.

Explanation:

Given:

F is given as 400N

one full additional earth radius formed

To Find:

Weight of the woman=?

Solution:

We know that gravitational force is inversely proportional to the square of radius.

f_g=\frac{1}{r^2}

where

f_g is the gravitational force

r^2 is the radius square

So when radius is doubled, the force becomes one fourth of the original.

Therefore \frac{1}{4} \times400 = 100N

3 0
3 years ago
Looking for help with this statics question
Serga [27]
The answer is 6.no got it right
6 0
3 years ago
Millikan measured the electron's charge by observing tiny charged oil drops in an electric field. Each drop had a charge imbalan
IceJOKER [234]

Answer:

4.8\cdot 10^{-19} C

Explanation:

For a drop in equilibrium, the weight is equal to the electric force (in magnitude):

W = F_e

where here we have

W=1.00\cdot 10^{-14}N is the weight of the drop

F_e is the magnitude of the electric force, which can be rewritten as

F_e = qE

where

q is the charge of the oil drop

E=2.08 \cdot 10^4 N/C is the magnitude of the electric field

Substituting into the equation and solving for q, we find the charge of the oil drop:

q=\frac{W}{F_e}=\frac{1.00\cdot 10^{-14}N}{2.08\cdot 10^4 N/C}=4.8\cdot 10^{-19} C

7 0
4 years ago
Other questions:
  • large cylindrical water tank is mounted on a platform with its central axis vertical. The water level is 3.75 m above the base o
    13·1 answer
  • Help ASAP<br> Answer question 3 please!!!
    15·1 answer
  • The formula for calculating work is ___.
    11·1 answer
  • If a 42kg rolling object slows from 11.5 m/s to 3.33 m/s how much work does friction do?
    6·1 answer
  • PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
    9·2 answers
  • Two movers are pushing a large crate with a force of 60.0 n each. one pushes north, the other east. what is the equilibrant forc
    15·1 answer
  • At 25 °C, a bottle contains 2.00 L of water in its liquid state. What is the volume of the water after it freezes (at 0 °C)? The
    15·1 answer
  • If a positively charged body is moved against an electric field it will gain?
    11·1 answer
  • A future use of space stations may be to provide hospitals for severely burned persons. It is very painful for a badly burned pe
    8·1 answer
  • A researcher reports an f-ratio with df = 3, 36 for an independent-measures experiment. how many treatment conditions were compa
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!