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vodomira [7]
4 years ago
11

The formula for calculating work is ___.

Physics
1 answer:
Orlov [11]4 years ago
3 0
Hey!

Formula for calculating work = Force × distance
Work done = Force applied on the object × distance travelled by it.

Hope it helps...!!!
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Please help with these physics problems 1. A soccer ball is dropped from the top of a building. It takes 5.8 seconds to fall to
Tatiana [17]

Answer:

1.) h = 164.8 m

2.) U = 49.1 m/s

3.) t = 1.43 seconds

Explanation:

1.) A soccer ball is dropped from the top of a building. It takes 5.8 seconds to fall to the ground. The height of the building is...? 

Since the soccer ball is dropped from the building, the initial velocity U will be equal to zero

Using second equation of motion

h = Ut + 1/2gt^2

Substitutes the time into the formula

h = 1/2 × 9.8 × 5.8^2

h = 164.8 m

2. The Falcon 9 launches to a height of 123 meters. What is its vertical initial velocity?

At maximum height final velocity = 0

Using the third law of motion

V^2 = U^2 - 2gH

0 = U^2 - 2 × 9.8 × 123

U^2 = 2410.8

U = 49.1 m/s

3. An apple falls from rest off a 10.m m tree. How long will it take before it hits the ground?

Since the apple fall from rest, the initial velocity U will be equal to zero

Using the second equation of motion,

h = Ut + 1/2gt^2

substitute all the parameters into the formula

10 = 1/2 × 9.8 × t^2

10 = 4.9t^2

t^2 = 10/4.9

t^2 = 2.04

t = 1.43 seconds

8 0
3 years ago
Guys hit that subscribe button↓<br> lets get this video to 10 likes!
Veronika [31]

Answer:

what

Explanation:

I can't understand

3 0
3 years ago
Read 2 more answers
find the gravitational force this shell exerts on a 1.60 kg point mass placed at the distance 5.01 m from the center of the shel
RideAnS [48]

The gravitational force of the shell exerts is 4.25m x 10¯¹² N.

We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses of objects. The magnitude of gravitational force can be determined as

F = G.m1.m2 / R²

where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.

From the question above, we know that

m1 = 1.6 kg

m2 = m

R = 5.01 m

By substituting the following parameters, we get

F = G.m1.m2 / R²

F = 6.674 × 10¯¹¹  . 1.6 . m / 5.01²

F = 4.25m x 10¯¹² N

where m is the mass of the shell

For more on gravitational force at: brainly.com/question/19050897

#SPJ4

7 0
1 year ago
a projectile whose masss is 10g is fired directly upward from ground level with an initial velocity of 1000m/s neglecting the ef
sammy [17]

Answer:

<em>The speed of the projectile when it impacts the ground is 1000 m/s</em>

Explanation:

<u>Vertical Launch</u>

When an object is launched vertically and upwards it starts to move at an initial speed vo, then the acceleration of gravity makes that speed to reduce until it reaches 0. The object has reached its maximum height. Then, it starts to move downwards in free fall, with initial speed zero and gradually increasing it until it reaches the ground level. We will demonstrate that the speed it has when impacts the ground is the same (and opposite) as the initial speed vo.

The speed when the object is moving upwards is given by

v_f=v_o-g.t

The time it takes to reach the maximum height is when vf=0, i.e.

0=v_o-g.t

solving for t

\displaystyle t=\frac{v_o}{g}

The maximum height reached is

\displaystyle y=\frac{gt^2}{2}=\frac{v_o^2}{2g}

Then, the object starts to fall. The object's height is given by

\displaystyle y=\frac{v_o^2}{2g}-\frac{gt'^2}{2}

where t' is the time the object has traveled downwards. The height will be 0 again when

\displaystyle \frac{v_o^2}{2g}=\frac{gt'^2}{2}

Solving for t'

\displaystyle t'=\frac{v_o}{g}

We can see the time it takes to reach the maximum height is the same it takes to return to ground level. Of course, the speed when it happens is

v_f=g.t'=v_o

Thus, the speed of the projectile when it impacts the ground is 1000 m/s

4 0
4 years ago
A stretched string is 2.11 m long and has a mass of 19.5 g. When the string oscillates at 440 Hz , which is the frequency of the
blsea [12.9K]

Answer:

The tension of the string is 41.876 N

Explanation:

Given;

length of the string, L = 2.11 m

mass of the string, m = 19.5 g = 0.0195 kg

frequency of the wave, f = 440 Hz

wavelength, λ = 15.3 cm = 0.153 m

The velocity of the wave is given by;

v = fλ

v = 440 x 0.153

v = 67.32 m/s

Also the velocity of the wave is given by

v = \sqrt{\frac{T}{\mu} }

where;

μ is mass per unit length = 0.0195 / 2.11 = 0.00924 kg/m

T is the tension of the string

T = v²μ

T = (67.32)²(0.00924)

T = 41.876 N

Therefore, the tension of the string is 41.876 N

5 0
4 years ago
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