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faust18 [17]
3 years ago
6

If a 42kg rolling object slows from 11.5 m/s to 3.33 m/s how much work does friction do?

Physics
1 answer:
lara31 [8.8K]3 years ago
4 0

Explanation:

work done by friction = 1/2 x 42 x ( 3.33^2 - 11.5^2)

= 21 ( 11.08 - 132.25)

= 21 ( - 121.17 )

= - 2544.57 J

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What is the relationship between temperature and altitude in the stratosphere? (2 points).
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What from the following list of statements about vectors is definitely true? (section 3.3) The magnitude of a vector can be smal
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6 0
3 years ago
Read 2 more answers
You push a disk-shaped platform tangentially on its edge 2.0 m from the axle. The platform starts at rest and has a rotational a
Natali [406]

Answer: 40.84 m

Explanation:

Given

Radius of the disk, r = 2m

Velocity of the disk, v = 7 rad/s

Acceleration of the disk, α = 0.3 rad/s²

Here, we use the formula for kinematics of rotational motion to solve

2α(θ - θ•) = ω² - ω•²

Where,

ω• = 0

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ω = 3.5 rad/s

2 * 0.3(θ - θ•) = 3.5² - 0

0.6(θ - θ•) = 12.25

(θ - θ•) = 12.25 / 0.6

(θ - θ•) = 20.42 rad

Since we have both the angle and it's radius, we can calculate the arc length

s = rθ = 2 * 20.42

s = 40.84 m

Thus, the needed distance is 40.84 m

7 0
3 years ago
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