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faust18 [17]
3 years ago
6

If a 42kg rolling object slows from 11.5 m/s to 3.33 m/s how much work does friction do?

Physics
1 answer:
lara31 [8.8K]3 years ago
4 0

Explanation:

work done by friction = 1/2 x 42 x ( 3.33^2 - 11.5^2)

= 21 ( 11.08 - 132.25)

= 21 ( - 121.17 )

= - 2544.57 J

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Answer:

Two marbles are launched at t = 0 in the experiment illustrated in the figure below. Marble 1 is launched horizontally with a speed of 4.20 m/s from a height h = 0.950 m. Marble 2 is launched from ground level with a speed of 5.94 m/s at an angle above the horizontal. (a) Where would the marbles collide in the absence of gravity? Give the x and y coordinates of the collision point. (b) Where do the marbles collide given that gravity produces a downward acceleration of g = 9.81 m/s2? Give the x and y coordinates.

Explanation:

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A train has a final velocity of 110 km/h. It accelerated for 36 s at 0.50 m/s2 . What was its initial velocity
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The initial velocity of the train  is 12.56 m/s.

<h3>Initial velocity</h3>

The initial velocity of the train can be determined by using the first kinematic equation as shown below;

v = u + at

u = v - at

where;

  • v is the final velocity = 110 km/h = 30.56 m/s
  • u is the initial velocity

u = 30.56 - (36 x 0.5)

u = 12.56 m/s

Thus, the initial velocity of the train  is 12.56 m/s.

Learn more about initial velocity here: brainly.com/question/19365526

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2 years ago
A sodium vapor lamp omit waves with the frequency of 5.26x10^14 Hz. What is the wavelength of light?
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Answer:

\lambda=5.70\times 10^{-7}\ m

Explanation:

The frequency of a sodium vapor lamp, f=5.26\times 10^{14}\ Hz

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c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{5.26\times 10^{14}}\\\\\lambda=5.70\times 10^{-7}\ m

So, the wavelength of light is equal to 5.70\times 10^{-7}\ m.

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