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iren2701 [21]
3 years ago
15

3. Combine like terms: 14 + 3 + 2c -20c Solve for x: x - 12= 20

Mathematics
1 answer:
Aneli [31]3 years ago
4 0

Answer:

-18c + 17

x = 32

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What is the value of x?​
LiRa [457]

Answer:

98°

Step-by-step explanation:

x = 53° + 45° { exterior angle of a triangle is equal to the sum of two opposite interior angles }

x = 98°

5 0
2 years ago
WORTH ALOT OF POINTS need help please
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3 years ago
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At parks elementary hot sandwiches are served on Mondays and Thursdays tacos on Tuesdays and salads on Wednesday’s if pizza was
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3 years ago
4.5÷6=<br>estimate the quotient ​
scZoUnD [109]

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0.75 - 0.8

Step-by-step explanation:

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The closest number to round 0.75 to is 0.8

3 0
3 years ago
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The travel-to-work time for residents in Ventura County is unknown. Assume the population variance is 39. How large should a sam
katen-ka-za [31]

Answer:

A sample size of 128 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.93}{2} = 0.035

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.035 = 0.965, so z = 1.81

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population(square root of the variance) and n is the size of the sample.

How large should a sample be if the margin of error is 1 minute for a 93% confidence interval

We need a sample size of n, which is found when M = 1. We have that \sigma = \sqrt{39}. So

M = z*\frac{\sigma}{\sqrt{n}}

1 = 1.81*\frac{\sqrt{39}}{\sqrt{n}}

\sqrt{n} = 1.81\sqrt{39}

(\sqrt{n})^2 = (1.81\sqrt{39})^2

n = 127.8

Rounding up

A sample size of 128 is needed.

7 0
3 years ago
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