Question

Which explains whether Kadesha is correct?

Answer 1

I believe the answer is the third one

Answer 2

Answer with explanation:

 Coordinates of vertices of ΔABC are =A(1,-1), B(1,-4),C(4,-4)

  Coordinates of vertices of ΔA'B'C' are =A'(1,5), B'(1,1),C(4,1)

Suppose, Preimage =ΔABC

Image =ΔA'B'C'

If you will find distance between two vertices of Both the triangles or length of sides of triangles

$AB=3\\\\BC=3\\\\AC=\sqrt{(4-1)^2+(-4+1)^2}\\\\AC=\sqrt{18}\\\\AC=3\sqrt{2}\\\\A'B'=4\\\\B'C'=3\\\\A'C'=\sqrt{(4-1)^2+(1-5)^2}\\\\A'C'=\sqrt{9+16}\\\\A'C'=5$

Option C is most Appropriate.

Kadesha is not correct because the number of units between points A and B is different than those between points A' and B'.