Answer:
The equation in point - slope form of a line that passes through the points (3,-5) and (-8,4) is: y-(-5) = -(9/11) (x-3) or y+5 = -(9/11) (x-3)
Step-by-step explanation:
P1=(3,-5)=(x1,y1)→x1=3, y1=-5
P2=(-8,4)=(x2,y2)→x2=-8, y2=4
Equation in Point-Slope Form: y-y1=m(x-x1)
Slope: m=(y2-y1)/(x2-x1)
Replacing the known values:
m=[4-(-5)] / (-8-3)
m=(4+5) / (-11)
m=(9) / (-11)
m=-(9/11)
Equation in the point - slope form:
y-(-5) = -(9/11) (x-3)
y+5 = -(9/11) (x-3)
Answer:
The correct answer is A I believe . . .
<u>Answer-</u>
The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

<u>Solution-</u>
Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)
The applying the distance formula,








Two equations are formed because one will be upper from the the given line and other will be below it.
Answer:
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Step-by-step explanation:
43+2(3-2)=43+2*3-2*2=43+6-4=45
Answer:
The answer is A.
Step-by-step explanation:
I learned it before.
Hope this helps.