Answer:
8.59
⋅
10
17
Explanation:
You can start by figuring out the energy of a single photon of wavelength
505 nm
=
505
⋅
10
−
9
m
.
To do that, use the equation
E
=
h
⋅
c
λ
Here
h
is Planck's constant, equal to
6.626
⋅
10
−
34
.
J s
c
is the speed of light in a vacuum, usually given as
3
⋅
10
8
.
m s
−
1
λ
is the wavelength of the photon, expressed in meters
Plug in your value to find--notice that the wavelength of the photon must be expressed in meters in order for it to work here.
E
=
6.626
⋅
10
−
34
J
s
⋅
3
⋅
10
8
m
s
−
1
505
⋅
10
−
9
m
E
=
3.936
⋅
10
−
19
J
So, you know that one photon of this wavelength has an energy of
3.936
⋅
10
−
19
J
and that your laser pulse produces a total of
0.338 J
of energy, so all that you need to do now is to find how many photons are needed to get the energy output given to you.
0.338
J
⋅
1 photon
3.936
⋅
10
−
19
J
=
8.59
⋅
10
17
photons
−−−−−−−−−−−−−−−−−
The answer is rounded to three sig figs.
H3C-CH2-CH2-CH3
<span>ion-ion bonds: not an ion </span>
<span>ion-dipole bonds: not an ion and no dipole </span>
<span>dipole-dipole bonds: butane is nonpolar, so no dipole </span>
<span>Hydrogen bonds: does not contain H bonded to F,O, or N </span>
<span>therefore the only intra-molecular bonds remaining are the weakest of the weak - london dispersion forces (aka Van Der Waals). These are randomly induced dipole attractions that happen when the electrons that move around randomly just happen to have a higher concentration at one end of the molecule. This causes dipoles to form in adjacent molecules, which induce dipoles in molecules next to them. these forces are very weak, but still play a part in raising the boiling point of butane.</span>
Answer:
Explanation: your answer to this question was 7. I think
Grams is the units of mass