Question

Consider the reaction: 3 A + 5 B --> 4 C. The rate of the reaction is found to be .7511 M/s. What is the rate of change of B? Be sure to consider whether the substance is disappearing or appearing in your answer.

Answer 1

Answer:

-3.7555 M/s is the rate of change of B.

Explanation:

3A + 5B  → 4C

Given that rate of the reaction ,R= 0.7511 M/s

Rate of the reaction is defined as change in concentration of any one of the reactant or product with respect to time.

$R=\frac{-1}{3}\frac{dA}{dt}=\frac{-1}{5}\frac{dB}{dt}=\frac{1}{4}\frac{dC}{dt}$

$R=0.7511 M/s=\frac{-1}{5}\frac{dB}{dt}$

$\frac{dB}{dt}=5\times 0.7511 M/s=-3.7555 M/s$

The negative sign indicates the concentration of reactant B is decreasing with progress in time. This mean reactant B is disappearing.

-3.7555 M/s is the rate of change of B.