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faust18 [17]
3 years ago
7

What is the quantity 0.0075 meters expressed in centimeters? use the table above to help you

Chemistry
2 answers:
Slav-nsk [51]3 years ago
8 0
From the conversion table:
1 meter = 100 cm

Therefore, all you need to do to convert <span>0.0075 meters to centimeters is cross multiplication as follows:
</span>0.0075 meters = (<span>0.0075 x 100) / 1 = 0.75 cm</span>
Vesnalui [34]3 years ago
5 0

<em>the quantity 0.0075 meters expressed in centimeters is </em><em> </em><em>0.75 cm</em>

<h3><em>Further explanation</em></h3>

Magnitude is something that can be measured or counted

The principal amount is the amount that has been determined based on the agreement of the scientists

Derivative magnitude is a quantity derived from the principal amount

7 main quantities have been determined based on international standards, namely:

1. Length, meters (m)

2. Time, second (s)

3. Mass, kilograms (kg)

4. Temperature, kelvin (K)

5. Light intensity, candela (cd)

6. Electric current, ampere (A)

7. Amount of substance, mol (m)

The length of the principal is to indicate the distance between two points in a place

The symbol is usually expressed in l, length

Length measurement can be used by several measuring instruments such as a ruler, caliper length, meter, screw micrometer

The main length unit consists of 7 units other than other units of length such as inches, miles, yards, feet:

Kilometer, km

Hectometer, hm

Dekameter, dam

Meter, m

Decimeter, dm

centimeter, cm

millimeters, mm

Each one unit descends then multiplied by 10, and if one unit increases then divided by 10

if we want to change the unit 0.0075 meters into centimeters, because units of meters to centimeters go down two units, then the number must be multiplied by 100

So that:

0.0075 x 100 = 0.75 cm

<h3><em>Learn more</em></h3>

convert length

brainly.com/question/618948

converting units brainly.com/question/8426032

conversion factor from km. to ft brainly.com/question/1462592

-----------------------------

<h3><em>Answer details</em></h3>

Grade: junior high school

Subject: physics

Chapter: quantities and units

Keywords: length, quantity, units, centimeters, meters

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If a 7.0 mL sample of vinegar was titrated to the stoichiometric equivalence point with 7.5 mL of 1.5M NaOH, what is the mass pe
NNADVOKAT [17]

First we need to calculate the number of moles of NaOH titrated.

molar concentration = number of moles / solution volume (liter)

number of moles = molar concentration × solution volume

number of moles of NaOH = 1.5 × 0.0075 = 0.01125 moles

Then we look at the chemical reaction:

CH_{3}-COOH +  NaOH = CH_{3}COONa + H_{2}O

We can see that 1 mole of acetic acid is reacting with one mole of sodium hydroxide. Then we can conclude that 0.01125 moles of sodium hydroxide reacts with 0.01125 moles of acetic acid.

Now we can get the mass of acetic acid:

number of moles = mass (grams) / molecular mass (g/mol)

mass = number of moles × molecular mass

mass of acetic acid = 0,01125 × 60 = 0.675 g

We assume that the density of the vinegar = 1 g/mL, so the mass percent of acetic acid is:

concentration of acetic acid = (mass of acetic acid / mass of vinegar) × 100

concentration of acetic acid = (0.674 / 7) ×  100 = 9.6 %

3 0
3 years ago
Arrange the following compounds in decreasing order of acidity from left to right, and explain the reason in less than 90 words.
saveliy_v [14]

Explanation:

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Since, fluorine, chlorine and bromine are all group 17 elements and fluorine is more reactive than chlorine. On the other hand, chlorine is more reactive than bromine.

Hence, ability to attract the electrons towards itself will be maximum in fluorine and least in bromine.

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8 0
3 years ago
A solution is prepared by dissolving 215 grams of methanol, ch3oh, in 1000. grams of water. what is the freezing point of this s
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Answer : The freezing point of the solution is, 260.503 K

Solution : Given,

Mass of methanol (solute) = 215 g

Mass of water (solvent) = 1000 g = 1 kg       (1 kg = 1000 g)

Freezing depression constant = 1.86^oC/m=1.86Kkg/mole

Formula used :

\Delta T_f=K_f\times m\\T^o_f-T_f=K_f\times \frac{w_{solute}}{M_{solute}\times w_{solvent}}

where,

T^o_f = freezing point of water = 100^oC=273K

T_f = freezing point of solution

K_f = freezing point constant

w_{solute} = mass of solute

w_{solvent} = mass of solvent

M_{solute} = molar mass of solute

Now put all the given values in the above formula, we get

273K-T_f=(1.86Kkg/mole)\times \frac{215g}{(32g/mole)\times (1kg)}

By rearranging the terms, we get the freezing point of solution.

T_f=260.503K

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3 years ago
A 2.00L flask was filled with 4.00 mol of HI at a certain temperature and given sufficient time to react. At equilibrium the con
inn [45]

Answer:

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Explanation:

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It is given that 4.00 mol of HI was filled in a flask of 2.00 L, thus, the concentration of HI will be,  

= 4.00 mol/2.00 L

= 2.00 mol/L

Based on the reaction, the initial concentration of 2HI is 2.00, H₂ is 0 and I₂ is O. The change in the concentration of 2HI is -x, H₂ is x and I₂ is x. The equilibrium concentration of 2HI will be 0.200-x, H₂ is x and I₂ is x.  

It is given that at equilibrium, the concentration of H₂ or x is 0.400 M.  

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= 1.20 M

The equilibrium concentration of I₂ will be,  

I₂ = x  

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The equilibrium constant (Keq) will be,  

Keq = [H₂] [I₂] / [HI]²

= (0.400) (0.400) / (1.20)²

= 0.112

Thus, the Keq of the reaction will be 0.112.  

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3 years ago
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Lemur [1.5K]
The answer would be 2.45 you know this
8 0
3 years ago
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