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Sphinxa [80]
3 years ago
8

What happens when an object experiences friction?

Physics
2 answers:
kaheart [24]3 years ago
5 0

Answer:Whenever a moving object experiences friction, some of its kinetic energy is transformed into thermal energy. Mechanical energy is always transformed into thermal energy due to friction. Mechanical energy is always transformed into thermal energy due to friction.

Explanation:

Whenever a moving object experiences friction, some of its kinetic energy is transformed into thermal energy. Mechanical energy is always transformed into thermal energy due to friction. Mechanical energy is always transformed into thermal energy due to friction.

Feliz [49]3 years ago
4 0

Answer:

its  A. because since heat energy means thermal i think it is A and also When friction acts between two surfaces that are moving over each other, some kinetic energy is transformed into heat energy.

Explanation: your welcome and i hope its right

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Addition of a metal slab of thickness "a" between the plates of a parallel plate capacitor of plate separation "d" is equivalent
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Answer:

K =  \frac{d}{d+a}

Explanation:

The capacitance of a capacitor in terms of the dielectric constant, area of the plate and the distance separating the plate is given by:

C = \frac{\epsilon A}{d}

Where A = Area of the plate

d = distance between the plates

\epsilon = dielectric constant

Case 1:

When a meta slab of thickness, a, is added between the plates of the parallel plate capacitor , the effective separation between the plates becomes d+a

Therefore the capacitance of the capacitor becomes:

  C = \frac{\epsilon A}{d + a} .......................(1)

Case 2:

Introducing a dielectric with dielectric constant K between the plates, the capacitance of the capacitor becomes:

C = \frac{K\epsilon A}{d}.........................(2)

Equating (1) and (2)

\frac{K\epsilon A}{d} = \frac{\epsilon A}{d+a}\\\frac{K}{d} = \frac{1}{d+a} \\K = \frac{d}{d+a}

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I think the puck pushes the stick backwards

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A 65.0 kg diver is 4.90 m above the water, falling at speed of 6.40 m/s. Calculate her kinetic energy as she hits the water. (Ne
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Answer:

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Explanation:

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Given: m = 65 kg, v = 6.4 m/s.

Substitute into equation 1

Ek = 1/2(65)(6.4²)

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Also,

Ep = mgh ............................ Equation 2

Where Ep =  Potential energy of the diver when its above the water, h = height of the diver above the water, g = acceleration due to gravity.

Given: m = 65 kg, h = 4.9 m, g = 9.8 m/s²

Substitute into equation 2.

Ep = 65(4.9)(9.8)

Ep = 3121.3 J.

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E = Ek+Ep

Where E = Kinetic energy of the diver when she hits the water.

E = 1331.2+3121.3

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f = ma

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a =  \frac{f}{m}
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