From the starting depth to the surface, the vertical distance is 35 ft.
From the surface to the peak of the jump, the vertical distance is 27 ft.
From the peak of the jump to the surface, the vertical distance is 27 ft.
From the surface to the ending depth, the vertical distance is 18 ft.
Then the total vertical distance is ...
35 ft + 27 ft + 27 ft + 18 ft = 107 ft
Answer:
A large area of a forest will likely have higher biodiversity than a smaller area of the same forest.
A half acre of rainforest would likely have greater biodiversity than a full acre of desert.
Explanation:
biodiversity of an ecosystem can be simply explain as the variability that exist in the ecosystem. These are difference that exist between living organism in terms of their habitat, their species and so on. However there exist different relationship between the area of ecosystem and the biodiversity of an ecosystem such that An ecosystem with large area of a forest will likely have higher biodiversity than a smaller area of the same forest.
Another one is that A half acre of rainforest would likely have greater biodiversity than a full acre of desert.
Answer:
(C) 40m/s
Explanation:
Given;
spring constant of the catapult, k = 10,000 N/m
compression of the spring, x = 0.5 m
mass of the launched object, m = 1.56 kg
Apply the principle of conservation of energy;
Elastic potential energy of the catapult = kinetic energy of the target launched.
¹/₂kx² = ¹/₂mv²
where;
v is the target's velocity as it leaves the catapult
kx² = mv²
v² = kx² / m
v² = (10000 x 0.5²) / (1.56)
v² = 1602.56
v = √1602.56
v = 40.03 m/s
v ≅ 40 m/s
Therefore, the target's velocity as it leaves the spring is 40 m/s