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3 years ago

What is the total energy change for the following reaction: CO + H2O -> CO2 + H2?

Chemistry

2 answers:

Katyanochek1 [597]3 years ago

5 0

Answer:

+132 kJ/mol

Explanation:

Founder's Education Educere Answer

liubo4ka [24]3 years ago

4 0

1)Delta H=(Delta H of reactants)-(Delta H of products)

2)And we know CO have 3 bond CO and CO2 have 2 bond that each of them are 2 bond, please see the picture!

so lets answer it:

$(3 \times 358) + (2 \times 463) - (4 \times 358) - 436 = 132$

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How many sig figs are there<br> 5.00000008

djverab [1.8K]

Answer:

2 sig figs.

Explanation:

Sig Fig Rules:

Any non-zero digit is a significant figure.

Any zeros between 2 non-zero digits are significant figures.

Trailing zeros after the decimal are significant figures.

6 0

4 years ago

Identify 5 things that would happen if there is not electricity.

Brilliant_brown [7]

If the power is out long enough even the city folks will run out of water. Many homes are all electric, so as soon at the lights are out they have no heat, no hot water and they can't cook. ... If the power is out, gas stations can't pump gas. Once generators run out of gas, those people will be in the dark too.

7 0

3 years ago

Read 2 more answers

CO(g)+2H2(g)⇌CH3OH(g)CO(g)+2H2(g)⇌CH3OH(g) This reaction is carried out at a different temperature with initial concentrations o

Katarina [22]

Answer:

9.4

Explanation:

The equation for the reaction can be represented as:

$CO_{(g)}$ + $2H_2O_{(g)}$ ⇄ $CH_3OH_{(g)}$

The ICE table can be represented as:

$CO_{(g)}$ + $2H_2_{(g)}$ ⇄ $CH_3OH_{(g)}$

Initial 0.27 0.49 0.0

Change -x -2x x

Equilibrium 0.27 - x 0.49 -2x x

We can now say that the concentration of $CH_3OH_{(g)}$ at equilibrium is x;

Let's not forget that at equilibrium $CH_3OH_{(g)}$ = 0.11 M

So:

x = [ $CH_3OH_{(g)}$ ] = 0.11 M

[ $CO_{(g)}$ ] = 0.27 - x

[ $CO_{(g)}$ ] = 0.27 - 0.11

[ $CO_{(g)}$ ] = 0.16 M

[ $2H_2_{(g)}$ ] = (0.49 - 2x)

[ $2H_2_{(g)}$ ] = (0.49 - 2(0.11))

[ $2H_2_{(g)}$ ] = 0.49 - 0.22

[ $2H_2_{(g)}$ ] = 0.27 M

$K_C = \frac{[CH_3OH]}{[CO][H_2]^2}$

$K_C = \frac{(0.11)}{(0.16)[(0.27)^2}$

$K_C = 9.4307$

$K_C$ = 9.4

∴ The equilibrium constant at that temperature = 9.4

8 0

3 years ago

For a reaction A + B → products, the following data were collected. Experiment Number Initial Concentration of A (M) Initial Con

Afina-wow [57]

Answer:

Rate constant k = 1.57*10⁻⁵ s⁻¹

Explanation:

Given reaction:

$A\rightarrow B$

Expt [A] M [B] M Rate [M/s]

1 3.40 4.16 1.82*10^-4

2 4.59 4.16 3.32*10^-4

3. 3.40 5.46 1.82*10^-4

$Rate = k[A]^{x}[B]^{y}$

where k = rate constant

x and y are the orders wrt to A and B

To find x:

Divide rate of expt 2 by expt 1

$\frac{3.32*10^{-4} }{1.82*10^{-4} } =\frac{[4.59]^{x} [4.16]^{y} }{[3.40]^{x} [4.16]^{y} }\\\\x =2$

To find y:

Divide rate of expt 3 by expt 1

$\frac{1.82*10^{-4} }{1.82*10^{-4} } =\frac{[3.40]^{x} [5.46]^{y} }{[3.40]^{x} [4.16]^{y} }\\\\y =0$

Therefore: x = 2, y = 0

$Rate = k[A]^{2}[B]^{0}$

To find k

Use rate for expt 1:

$k = \frac{Rate1}{[A]^{2} } =\frac{1.82*10^{-4}M/s }{[3.40]^{2} } =1.57*10^{-5} s-1$

6 0

3 years ago

the separation of ink into its different pigments during chromatography is a a. solubility b. physical property c. physical chan

madreJ [45]

c. physical change

Explanation:

The separation of ink into its different pigments during chromatography is a physical change.

Ink is a mixture of many different pigments.

During chromatography, a mixture is separated based on the relative migration of constituents of mixture over an adsorbent.

Separation techniques are used to celebrate mixtures based on their physical properties.
During a physical change only the physical properties of matter like their form and state is changed.
The process is easily reversible and no new kinds of matter are formed.

learn more:

Physical property brainly.com/question/10972073

#learnwithBrainly

7 0

4 years ago