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allochka39001 [22]
3 years ago
7

The so-called Livestock Evolution involves increased consumption of animal products in developing countries.

Chemistry
1 answer:
Rama09 [41]3 years ago
4 0
This is probably true but I’m not 100% sure
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Someone please help me with question 4 ! EXTRA POINTS
Aleks04 [339]
1. B
2. C
3. A
That should do it
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3 years ago
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What does conserving mass mean in a chemical equation?
Keith_Richards [23]
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What are dipoles, and what is the difference between a natural dipole and an induced dipole?
Tasya [4]

Answer:

See explanation below.

Explanation:

Dipoles are molecules that have partial charges. It happens because of the difference in electronegativity of the elements. This property is the tendency that the atom has to take the electron to it, so, in the covalent bond, the shared pair of electrons is easily found at the more electronegativity atom, and so, it has a partial negative charge, and the other, a partial positive charge. This is a natural dipole.

If the difference of electronegativity is 0, or extremely close to 0, then the molecule is nonpolar, and so the molecule doesn't have partial charges. But, to be joined together and form the substance, the partial charge must be induced, so it's an induced dipole.

7 0
3 years ago
A bar graph of boiling point of milk and water​
kap26 [50]

Answer:

The boiling point of milk is close to the boiling point of water, which is 100 degrees C, or 212 degrees F at sea level, but milk contains additional molecules, so its boiling point is slightly higher.

Explanation:

5 0
2 years ago
Cuando se quema 1 mol de metano –o sea, 16 g–, se desprenden 802
Anvisha [2.4K]

Answer:

1 gramo de metano aporta 50.125 kilojoules.

1 gramo de metano aporta 48.246 kilojoules.

Explanation:

La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo (Q), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto (\bar {Q}), en kilojoules por mol, dividido por su masa molar (M), en gramos por mol:

Q = \frac{\bar Q}{M} (1)

A continuación, analizamos cada caso:

Metano

Q = \frac{802\,\frac{kJ}{mol} }{16\,\frac{g}{mol} }

Q = 50.125\,\frac{kJ}{g}

1 gramo de metano aporta 50.125 kilojoules.

Octano

Q = \frac{5500\,\frac{kJ}{mol} }{114\,\frac{g}{mol} }

Q = 48.246\,\frac{kJ}{mol}

1 gramo de metano aporta 48.246 kilojoules.

3 0
2 years ago
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