Answer:
K2 = 9.701 x 10^-10
Explanation:
K1 = 4.0 x 10^-5
K2 = ?
T1 = -10.8 °C +273 = 262.2K
T2 = -16 °C + 273 = 257K
ΔHrxn = 120. kJ/mol = 120000 J/mol
The formular relating all these parameters is given as;
ln( K2 / K1) = −ΔHrxn / R * (1 / T2 − 1 / T1)
ln (K2 / 4.0 x 10^-5) = - 120000 / 8.314 (1 / 257 - 1 / 262.2)
ln (K2 / 4.0 x 10^-5) = 1.1138
ln K2 - ln4.0 x 10^-5 = 1.1138
ln K2 = 1.1138 + ln4.0 x 10^-5
ln K2 = 1.1138 - 10.1266
ln K2 = -9.0128
K2 = 9.701 x 10^-10
The approximate degree of dissociation of a 0.35 M solution of lactic acid is 4,87%
<h3>What is degree of dissociation?</h3>
The degree of dissociation is the quantity used to express the strength of a base, that is, its ability to conduct electric current, which depends on the amount of ions released in the dissociation.
The degree of dissociation (α) is another way of determining the strength of a base. It indicates the fatty acids that were released from a base when it dissociates in water.
With that being said, C stands for concentration and α is the the degree of dissociation.
Latic Acid can be written as C3H6O3
![Ka = \frac{[H^{+}] [CH3CH(OH)CO2^{-}] }{CH#CH(OH)CO2H} = \frac{C^{2} \alpha^{2} }{C(1-\alpha )} = \frac{C\alpha ^{2} }{(1-\alpha )}](https://tex.z-dn.net/?f=Ka%20%3D%20%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%20%5BCH3CH%28OH%29CO2%5E%7B-%7D%5D%20%20%7D%7BCH%23CH%28OH%29CO2H%7D%20%3D%20%5Cfrac%7BC%5E%7B2%7D%20%5Calpha%5E%7B2%7D%20%20%7D%7BC%281-%5Calpha%20%29%7D%20%3D%20%5Cfrac%7BC%5Calpha%20%5E%7B2%7D%20%7D%7B%281-%5Calpha%20%29%7D)
As α is too small (1-α) can be neglected.
![Ka = C\alpha ^{2} \\\\\\alpha = \sqrt[]{\frac{Ka}{C} }](https://tex.z-dn.net/?f=Ka%20%3D%20C%5Calpha%20%5E%7B2%7D%20%20%5C%5C%5C%5C%5C%5Calpha%20%20%20%20%3D%20%5Csqrt%5B%5D%7B%5Cfrac%7BKa%7D%7BC%7D%20%7D)
In this case, is possible to see that approximate degree of dissociation of a 0.35 M solution of lactic acid is 4,87%
See more about pKa at: brainly.com/question/14924722
#SPJ1
Answer: Gas
Explanation:
Gas. The arrows represent direction. They are moving around in the box extremely fast, and are not compact like a solid or liquid.
One
molar mass NaCl
Na = 23
Cl =35.5
Molar mass = 58.6
mols = 450 / 58.5
mols = 7.69 mols
Concentration = mols / L
mols = 7.69
Volume = 4.5 kg = 4.5 L [1 liter weighs 1 kg]
C = 7.69 mol / 4.5 L
C = 1.71 mol/L
The question is unclear. I'm taking this to mean that you don't change the number of moles; you merely add 0.5 L to the volume.
Answer C = 7.69 / 5L = 1.54 mol / L
Two
I'm going to leave this. The wording just is not clear.
Three
More than you could grow in the entire planet earth for many centuries.
Ratio of sugar = 10 / (40 + 10 + 500) = 10 / 550 = 1:55 or 0.0182 to 1
Four
Guava Juice = (36 / 100 ) * 100% = 36%
Water = (64/100 ) * 100 = 64%
Answer:
number of moles = 6.393 moles
Explanation:
One mole of any substance contains Avogadro's number (6.022 * 10^23) of atoms.
Therefore, to know the number of moles that contain 3.85 * 10^24 atoms, all we have to do is cross multiplication as follows:
1 mole ......................> 6.022 * 10^23
?? moles ..................> 3.85 * 10^24
number of moles = (3.85 * 10^24 *1) / (6.022 * 10^23)
number of moles = 6.393 moles
Hope this helps :)
