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Elena-2011 [213]

2 years ago

15

In an experiment, a scientist adds radioactive oxygen to different parts of the environment in which he grows his plants. Based

on the chemical equation, adding radioactive oxygen in which component would produce radioactive glucose? Choose the correct answer.
A. air
B. Water
C. Energy
D. Fertilizer

1 answer:

vladimir1956 [14]2 years ago

8 0

Answer:

D

Explanation:

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Which measurement, temperature or volume, limits the precision of the data obtained in the experiment? explain?

GrogVix [38]

The answer is volume that is volume limits the precision of data obtained in an experiment .

As while pouring of the liquids, we control the volume, but it can have been off. And this could results in the wrong mole to mole ratio.Thus it limits the precision, So the answer is that volume limits the precision of data obtained in an experiment .

6 0

3 years ago

start out as one kind of rock, but large amounts of pressure and heat change them into a different kind.

Eddi Din [679]

Answer:

Metamorphic

Explanation:

6 0

2 years ago

4) What volume will the gas in the balloon at right occupy at 250k?<br><br> balloon: 4.3L 350K

swat32

Answer:

2.87 liter.

Explanation:

Given:

Initially volume of balloon = 4.3 liter

Initially temperature of balloon = 350 K

Question asked:

What volume will the gas in the balloon occupy at 250 K ?

Solution:

By using:

$Pv =nRT$

Assuming pressure as constant,

V∝ T

Now, let K is the constant.

V = KT

Let initial volume of balloon , $V_{1}$ = 4.3 liter

1000 liter = 1 meter cube

1 liter = $\frac{1}{1000} m^{3} = 10^{-3} m^{3$

4.3 liter = $4.3\times10^{-3}=4.3\times10^{-3} m^{3}$

And initial temperature of balloon, $T_{1}$ = 350 K

Let the final volume of balloon is $V_{2}$

And as given, final temperature of balloon, $T_{2}$ is 250 K

Now, $V_{1} = KT_{1}$

$4.3\times10^{-3}=K\times350\ (equation\ 1 )$

$V_{2} = KT_{2}$

$=K\times250\ (equation 2)$

Dividing equation 1 and 2,

$\frac{4.3\times10^{-3}}{V_{2} } =\frac{K\times350}{K\times250}$

K cancelled by K.

By cross multiplication:

$350V_{2} =4.3\times10^{-3} \times250\\V_{2} =\frac{ 4.3\times10^{-3} \times250\\}{350} \\ = \frac{1075\times10^{-3}}{350} \\ =2.87\times10^{-3}m^{3}$

Now, convert it into liter with the help of calculation done above,

$2.87\times10^{-3} \times1000\\2.87\times10^{-3} \times10^{3} \\2.87\ liter$

Therefore, volume of the gas in the balloon at 250 K will be 2.87 liter.

4 0

3 years ago

How many liters of 1.75 M solution could be made using 35 grams of NaCl?

dolphi86 [110]

Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)

Formula:
$M = \frac{m}{MM*V}$

Solving:
$M = \frac{m}{MM*V}$
$1.75 = \frac{35}{58.44*V}$
$1.75*58.44V = 35$
$102.27V = 35$
$V = \frac{35}{102.27}$
$\boxed{\boxed{V \approx 0.34\:L}}\end{array}}\qquad\quad\checkmark$

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2 years ago

A(n) ____ consists of atoms that have a specific number of protons in their nuclei.

Kamila [148]

Answer:

Solution i think

Explanation:

7 0

2 years ago