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maksim [4K]
3 years ago
9

What is the term for a substance capable of dissolving another substance?

Chemistry
1 answer:
AURORKA [14]3 years ago
3 0

Answer:

The answer to your question is: solvent

Explanation:

Solvent is a component in a solution that is present in the highest amount and is able to dissolve the other or others components.

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A certain gas is present in a 10.0 LL cylinder at 4.0 atmatm pressure. If the pressure is increased to 8.0 atmatm the volume of
ICE Princess25 [194]

Answer:

The gas obeys Boyle’s law and the value of k_i\&k_f both are equal to 40.0 atm L.

Explanation:

Initial volume of the gas = V_1=10.0 L

Initial pressure of the gas = P_1=4.0 atm

Final volume of the gas = V_2=5.0 L

Final pressure of the gas = P_2=8.0 atm

This law states that pressure is inversely proportional to the volume of the gas at constant temperature.  

PV=k

The equation given by this law is:

P_1V_1=P_2V_2

P_1\propto \frac{1}{V_1}

P_1V_1=k_i

k_i=4.0 atm\times 10.0 L = 40.0 atm L

P_2\propto \frac{1}{V_2}

P_V_2=k_f

k_f=8.0 atm\times 5.0 L = 40.0 atm L

k_i=k_f=40.0 atm L

The gas in the cylinder is obeying Boyle's law.

The gas obeys Boyle’s law and the value of k_i\&k_f both are equal to 40.0 atm L.

6 0
3 years ago
What would you need to do to calculate the molality of 10 g of NaCl in 2 kg of
jasenka [17]

Answer:

O B. Convert the 10 g of NaCl to moles of NaCl.

Explanation:

The formula for finding the molality is m=moles of solute/kg of solvent. The solute for this question is NaCl and the solvent is water.

(10g NaCl)(1 mol NaCl/58.44g NaCl)=0.1711 mol NaCl

58.44 is the molar mass of NaCl

m=0.1711 mol NaCl/2 kg H2O

m=0.085557837

7 0
3 years ago
How many molecules are in 85 grams of Silver?
densk [106]

Answer:

3.0 × 10

3.0 \times  {10}^{23}

molecules

Explanation:

there are many molecules

8 0
3 years ago
There are two types of circuits we can make and they are ...
erma4kov [3.2K]
They are

parallel circuit and series circuit
4 0
3 years ago
In this salt water floating egg experiment, how will you use these calculations to find the density of the egg? I’m really confu
Agata [3.3K]

Glass 1 Freshwater  

The egg went directly to the base of the glass. Consequently it has sunk and did not drift  

237.0  

237 (1 glass)  

1.000

Glass 2  

Water with 2 teaspoons of salt  

A similar outcome for glass 2 as container 1 when egg was set into the container it sank to the base.  

248.4  

237  

1.048

Glass 3  

Water with 3 teaspoons of salt  

In reference to glass 1 and 2 the egg sank to the base for a third time.  

254.1  

237  

1.072  

Glass 4  

Water with 4 teaspoons of salt  

The egg remained gliding to where a little bit of the egg was standing out on the top, and when pushed down the egg returned up.  

259.8  

237  

1.096

Hope this helps!

5 0
3 years ago
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