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worty [1.4K]
3 years ago
15

If a triangle is a right triangle then the other two angles must be acute true or false ?

Mathematics
1 answer:
kolezko [41]3 years ago
8 0

Answer:

The sum of the angles in any triangle is 180 degrees. If one of the three angles is 90 degrees (a right angle) the the sum of the other two angles is 90 degrees. Therefore each of the other two angles must be acute.

The statement is TRUE.

Step-by-step explanation:


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Find the HCF and LCM of 4x^2 - 36 ,2x^2 - 12x + 18 and 2x^2 + x - 21​
olga_2 [115]

Answer:

(x-3), 4 (x - 3)^2 (x + 3) (2 x + 7)

Step-by-step explanation:

Factor all the expressions,

1st expression= 4x^2 - 36=4(x^2-9)=4(x+3)(x-3)

2nd expression=2x^2 - 12x + 18 =2(x^2-6x+9)=2 (x - 3)^2=2(x-3)(x-3)

3rd expression=2x^2 + x - 21​=(x - 3) (2 x + 7)

HCF=Commo factor=(x-3)

LCF=Common factor*Remaining factor=4(x+3)(x-3)(x-3) (2 x + 7)=4 (x - 3)^2 (x + 3) (2 x + 7)

4 0
3 years ago
Naomi has earned $54 mowing lawns the past two days. she worked 2 1/2 hours yesterday and 4 1/4 hours today. if naomi is paid th
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7 0
3 years ago
Find the missing angle measures
emmasim [6.3K]

Answer:

see below

Step-by-step explanation:

Assuming s and t are parallel

The two angles are same side interior angles and same side interior angles add to 180 when the lines are parallel

4x-12 + 120 = 180

4x -12 = 60

4x = 72

x = 18

That means 4x -12 = 4(18) -12 = 60

Vertical angles are equal.    Alternate interior angles are equal.  Alternate exterior angles are equal.  All pink dot angles are equal.

Pink dots are 60 degrees

All blue lines are equal.  They are 120 degrees

4 0
3 years ago
Read 2 more answers
Uh little confused on this one uh oh.
lana [24]

Answer:

I uhh need the question.. lol

Step-by-step explanation:

cat is 31%

dog is 42%

hamster is 19%

fish is 8%

62+84+38+16=200

62/200=0.31

84/200=0.42

38/200=0.19

16/200=0.08

Have a nice day!

7 0
3 years ago
In the piecewise function shown below, what is the f(10)?
svetlana [45]

B. because 15 is not equal too 10

5 0
3 years ago
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