Particles in gaseous state have the greatest distance between them. This is because the gas particles have a greater kinetic energy because of which they move far apart from each other. If we take water, in steam (water vapor) the particles are far apart from each other when compared to liquid water and solid ice.
Answer: The freezing point depression is ![1.86^0C](https://tex.z-dn.net/?f=1.86%5E0C)
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
= freezing point constant =
m= molality =
Thus freezing point depression is ![1.86^0C](https://tex.z-dn.net/?f=1.86%5E0C)
Answer:
The critical temperature of a substance is the temperature at and above which vapour of the substance cannot be liquefied, no matter how much pressure is applied.
Answer:
964ug
Explanation:
The problem here involves converting from one unit to another.
We are to convert from ounces to micrograms.
1ug = 1 x 10⁻⁶g
1oz = 28.35g
So we first convert to grams from oz then take to ug:
Solving:
1oz = 28.35g
3.4 x 10⁻⁵oz will then give 3.4 x 10⁻⁵ x 28.35 = 9.64 x 10⁻⁴g
So;
1 x 10⁻⁶g = 1ug
9.64 x 10⁻⁴g will give
= 9.64 x 10²ug or 964ug
Answer:
32.7 kilograms of aluminium oxide will be produced.
Explanation:
![2 Al ( s ) + Fe_2O_3 ( s ) +heat\rightarrow Al_2O_3 ( s ) + 2 Fe ( l )](https://tex.z-dn.net/?f=2%20Al%20%28%20s%20%29%20%2B%20Fe_2O_3%20%28%20s%20%29%20%2Bheat%5Crightarrow%20Al_2O_3%20%28%20s%20%29%20%2B%202%20Fe%20%28%20l%20%29)
Mass of aluminum = 17.3 kg = 17300 g (1 kg = 1000 g )
Moles of aluminium = ![\frac{17300 g}{27 g/mol}=640.74 mol](https://tex.z-dn.net/?f=%5Cfrac%7B17300%20g%7D%7B27%20g%2Fmol%7D%3D640.74%20mol)
According to reaction, 2 moles of aluminum gives 1 mole of aluminum oxide,then 640.74 moles of aluminum will give:
of aluminum oxide
Mass of 320.37 moles of aluminum oxides:
320.37 mol × 102 g/mol = 32,677.74 g = 32.67774 kg ≈ 32.7 kg
32.7 kilograms of aluminium oxide will be produced.