Answer:
The probability that they purchased a green or a gray sweater is 
Step-by-step explanation:
Probability is the greater or lesser possibility of a certain event occurring. In other words, probability establishes a relationship between the number of favorable events and the total number of possible events. Then, the probability of any event A is defined as the quotient between the number of favorable cases (number of cases in which event A may or may not occur) and the total number of possible cases. This is called Laplace's Law.

The addition rule is used when you want to know the probability that 2 or more events will occur. The addition rule or addition rule states that if we have an event A and an event B, the probability of event A or event B occurring is calculated as follows:
P(A∪B)= P(A) + P(B) - P(A∩B)
Where:
P (A): probability of event A occurring.
P (B): probability that event B occurs.
P (A⋃B): probability that event A or event B occurs.
P (A⋂B): probability of event A and event B occurring at the same time.
Mutually exclusive events are things that cannot happen at the same time. Then P (A⋂B) = 0. So, P(A∪B)= P(A) + P(B)
In this case, being:
- P(A)= the probability that they purchased a green sweater
- P(B)= the probability that they purchased a gray sweater
- Mutually exclusive events
You know:
- 8 purchased green sweaters
- 4 purchased gray sweaters
- number of possible cases= 12 + 8 + 4+ 7= 21
So:
Then:
P(A∪B)= P(A) + P(B)
P(A∪B)= 
P(A∪B)= 
<u><em>The probability that they purchased a green or a gray sweater is </em></u>
<u><em></em></u>
Every color except blue. The blue color bounces off the object into our eyes.
Answer:
The roots (zeros) of the function are:

Step-by-step explanation:
Given the function

substitute f(x) = 0 to determine the zeros of the function

First break the expression x² + 3x - 40 into groups
x² + 3x - 40 = (x² - 5x) + (8x - 40)
Factor out x from x² - 5x: x(x - 5)
Factor out 8 from 8x - 40: 8(x - 5)
Thus, the expression becomes

switch the sides

Factor out common term x - 5

Using the zero factor principle
if ab=0, then a=0 or b=0 (or both a=0 and b=0)

Solve x - 5 = 0
x - 5 = 0
adding 5 to both sides
x - 5 + 5 = 0 + 5
x = 5
solve x + 8 = 0
x + 8 = 0
subtracting 8 from both sides
x + 8 - 8 = 0 - 8
x = -8
Therefore, the roots (zeros) of the function are:

Answer:
48 because length times width.
where's the number line?
maybe u can attach it at the comments:)