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2 years ago

Please help me I need to pass a test!!!! ITS A MAJOR GRADE!!!

Mathematics

2 answers:

alekssr [168]2 years ago

5 0

Answer:

Step-by-step explanation:

Arisa [49]2 years ago

3 0

It’s would be C due to the “or” part of it and it pointing to the left

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How to tell if something is a function.

insens350 [35]

Answer:

it is when it can make a mathematical statement

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2 years ago

A group of 169 students needs to be seated in a square formation for a

otez555 [7]

We have a group of 169 students that needs to be seated in a square formation. Then, the number of rows has to be the square root of 169 :-

$r = \sqrt{169} = 13$

Then, a square of 13 rows and 13 columns will fit the 169 students.

If the number of students is 1024, then the number of rows <em>N </em>can be calculated as :-

${N}^{2} = 1024$

$N = \sqrt{1024}$

$N = 32$

<h3><u>Final Answer :-</u></h3>

169 students will seat in a 13×13 formation.

1024 students will seat in a 32×32 formation (N=32)

-------------------<em>★</em><em>-</em>------------------

6 0

3 years ago

What is the domain of y = cos θ

ElenaW [278]

All real numbers / all x
if you're asking for range as well then its -1<x<1

5 0

3 years ago

Read 2 more answers

How do you get the answer to this problem?<br> (2^3)(2^-7)

postnew [5]

(2^3)=2*2*2=8
(2^-7)=1/2*1/2*1/2*1/2*1/2*1/2*1/2=1/128
8*1/128=1/16=.0625

7 0

3 years ago

You have been assigned to determine whether more people prefer Coke or Pepsi. Assume that roughly half the population prefers Co

Alex Ar [27]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

Step-by-step explanation:

For this case we have the following info given:

$ME=0.03$ the margin of error desired

$Conf= 0.95$ the level of confidence given

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

the critical value for 95% of confidence is $z=1.96$

We can use as estimator for the population of interest $\hat p=0.5$ . And on this case we have that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

3 0

3 years ago