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Alisiya [41]
3 years ago
13

1 l of gas at standard temperature and pressure is compressed to 473ml. what is the new pressure of the gas?

Chemistry
1 answer:
OlgaM077 [116]3 years ago
5 0
I thunk its 2.11 atm

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Which member of each pair of compounds forms intermolecular H bonds? Draw the H-bonded structures in each case:
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FCH₂CH₂F will form Intermolecular Hydrogen bond

FCH₂CH₂F has H-F atoms linked together by Hydrogen bond whereas in HOCH₂CH₂OH here, carbon is linked with oxygen and oxygen is again linked with Hydrogen.

<h3>What is Intermolecular Hydrogen bond ?</h3>

Intermolecular hydrogen bonding refers to the formation of hydrogen bonds between molecules of the same or distinct substances. As an illustration, consider hydrogen bonds in water, alcohol, ammonia, etc.

  • An illustration. (i) hydrogen connection between the hydrogen fluoride molecules. (ii) The hydrogen bond in molecules of alcohol or water

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Answer: Resting position
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Under what circumstances will a scientific theory be changed or discarded
VMariaS [17]

If new evidence or observations falsify a scientific theory, the theory will have to be changed to adapt to the new data or just discarded altogether.

7 0
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If an acid has a ka=1.6x10^-10, what is the acidity of the solution?
LUCKY_DIMON [66]
The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
 In order to determine the acidity of the solution, the half titration point value is needed, this will make it possible to determine the value of H30+.  If the half point titration value is known, then Ka will be equivalent to pH and the value will be evaluated using the equation: - log (1.6 * 10^-10).
5 0
3 years ago
An unknown compound is processed using elemental analysis and found to contain 117.4g of platinum 28.91 carbon and 33.71g nitrog
dlinn [17]

Answer:

1 mole of platinum

Explanation:

To obtain the number of mole(s) of platinum present, we need to determine the empirical formula for the compound.

The empirical formula for the compound can be obtained as follow:

Platinum (Pt) = 117.4 g

Carbon (C) = 28.91 g

Nitrogen (N) = 33.71 g

Divide by their molar mass

Pt = 117.4 / 195 = 0.602

C = 28.91 / 12 = 2.409

N = 33.71 / 14 = 2.408

Divide by the smallest

Pt = 0.602 / 0.602 = 1

C = 2.409 / 0.602 = 4

N = 2.408 / 0.602 = 4

The empirical formula for the compound is PtC₄N₄ => Pt(CN)₄

From the formula of the compound (i.e Pt(CN)₄), we can see clearly that the compound contains 1 mole of platinum.

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