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Tanya [424]
3 years ago
5

A closed system consists of 0.3 kmol of octane occupying a volume of 5 m³. Determine (a) the weight of the system, in N, and (b)

the molar- and mass-based specific volumes, in m³/kmol and m³/kg respectively. Let g=9.81m/s².
Engineering
1 answer:
Leni [432]3 years ago
7 0

Answer:

a) m=336.18N

b) Vn=16.67m/kmol

Vm=0.1459m^3/kg

Explanation:

To calculate the mass of the octane(m):

Number of mole of octane (n) =0.3kmol(given)

Molarmass of octane (M) =114.23kg/kmol

m=n*M

m=(0.3kmol)*(114.23kg/kmol)

m=34.269kg

To calculate for the weight of octane(W):

W=g*m

W=(9.81m/s^2)*(34.269kg)

W=336.18N

b) For specific volumes of Vn and Vm:

Given volume of octane (V) =5m^3

Vm=V/m

Vm=5m^3/34.269kg

Vm=0.1459m^3/kg

And Vn will be :

Vn=V/m=5m^3/0.3kmol

Vn=16.67m/Kmol

Therefore, the answers are:

a) m=336.18N

b) Vn=16.67m/kmol

Vm=0.1459m^3/kg

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Lelu [443]

This question is incomplete, The missing image is uploaded along this answer below;

Answer:

the maximum stress in the cylinder is 3.23 ksi

 

Explanation:

Given the data in the question and the diagram below;

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we substitute

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T = 34.16149 lb.ft

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Now, the volume will be;

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V = 508.938 in³

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Initial energy per unit volume = Strain energy per volume

⇒ T/V = σ²/2E

from the image; E = 6.48(10⁶) kip

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508.938σ² =  5,312,794,924.8

σ² = 10,438,982.5967  

σ = √10,438,982.5967

σ = 3230.9414  

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Therefore, the maximum stress in the cylinder is 3.23 ksi

8 0
3 years ago
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Answer:

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 2. Electrically actuated

3.Pneumatically actuated

Explanation:

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Where the silicon rubber is made ?
lubasha [3.4K]

Answer:

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Explanation:

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Sergeu [11.5K]

Answer:

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Explanation:

Please check attachment for complete solution and step by step explanation

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