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RoseWind [281]
4 years ago
5

Colin is filling 4.5 ounce bottles with lavender bubble bath that he made for gifts.He was able to fill 7.5 bottles.How many oun

ces of bubble bath did he make.
Mathematics
1 answer:
icang [17]4 years ago
4 0
4.5 *7.5 =33.75 ounces
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What is the area of the figure? <br> A. 54 cm2<br> B. 42 cm2<br> C. 54 cm<br> D. 42 cm
serg [7]

Answer

The area is 54cm² To get the area i split the shape into two shape both having a length of 9in and a width of 3in. I calculate the area for one by using lxw=area and get 27 and times that by two to get 54.

When calculating the area for this object you get 54 and you add the ²symbol because its area is not one dimensioned it is two dimensioned or length times width not just length, so you use the ² symbol to show that.

6 0
3 years ago
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Ill give brainlest again!!!!!!!!!!!!!!!
mash [69]

Answer:

40

Step-by-step explanation:

the range is the number between the highest and lowest number. the lowest in this is 5 and the highest is 45

45-5=40

3 0
3 years ago
Quadratic equation has 5x+0 as a linear factor what value is a zero of the associated quadratic function.
natka813 [3]

9514 1404 393

Answer:

  x = 0

Step-by-step explanation:

The zero is the value of x that makes the linear factor zero:

  5x +0 = 0

  5x = 0 . . . . . simplify

  x = 0/5 = 0 . . . . divide by 5

The associated zero is x = 0.

7 0
3 years ago
3) Postcards: Marcie wants to make a box to hold her postcard collection from a piece of
klasskru [66]

The volume of the box is the amount of space in it.

The dimension of the postcard is:

\mathbf{Length = 10}

\mathbf{Width = 18}

Let x represents the length of the cut.

So, the dimension of the box is:

\mathbf{Length = 10 -2x}

\mathbf{Width = 18 -2x}

\mathbf{Height = x}

<u>(a) The function that represents the volume of the box</u>

This is calculated as:

\mathbf{V(x) = Length \times Width \times Height}

So, we have:

\mathbf{V(x) = (10 - 2x) \times (18 - 2x) \times x}

Expand

\mathbf{V(x) = 180x - 56x^2 + 4x^3}

Hence, the volume function is: \mathbf{V(x) = 180x - 56x^2 + 4x^3}

<u>(b) The dimension that maximizes the volume</u>

We have:

\mathbf{V(x) = 180x - 56x^2 + 4x^3}

Differentiate

\mathbf{V'(x) = 180- 112x + 12x^2}

Set to 0

\mathbf{180- 112x + 12x^2 = 0}

Using a calculator, we have:

\mathbf{x = 7.3,2.1}

The value x = 7.3 is greater than the dimension of the box.

So, we have:

\mathbf{x = 2.1}

Recall that:

\mathbf{Length = 10 -2x}

\mathbf{Width = 18 -2x}

\mathbf{Height = x}

So, we have:

\mathbf{Length = 10 -2 \times 2.1 = 5.8}

\mathbf{Width = 18 -2 \times 2.1 = 13.8}

\mathbf{Height = 2.1}

Hence, the dimension that maximizes the volume is 5.8 by 13.8 by 2.1

<u>(c) The maximum volume</u>

This is calculated as the product of the dimension of the box

So, we have:

\mathbf{Volume = 5.8 \times 13.8 \times 2.1}

\mathbf{Volume = 168.1}

Hence, the maximum volume of the box is 168.1 cubic inches

Read more about volumes at:

brainly.com/question/17056191

5 0
3 years ago
Solve for m 18m-13m=25 m=
sveta [45]

Answer:

m=0

Step-by-step explanation:

5 0
3 years ago
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