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Natasha2012 [34]
3 years ago
15

A firm produces a commodity and receives $100 for each unit sold. The cost of producing and selling x units is 20x 0.25x 2 dolla

rs. Find the number of units the company should produce in order to maximize profit, and find the maximum profit.
Mathematics
1 answer:
vekshin13 years ago
4 0

Answer:

160 units and $6400

Step-by-step explanation:

We have that the cost per x unit is: 20 * x + 0.25 * x ^ 2

the price per unit is 100, therefore revenue for each unit would be 100 * x

However:

profit = revenue - cost

p (x) = 100 * x - 20 * x - 0.25 * x ^ 2

for the maximum value profit we must derive and equal 0:

p '(x) = 100 - 20 - 0.5 * x

0 = 80 - 0.5 * x

0.5 * x = 80

x = 80 / 0.5

x = 160

Therefore, the maximum profit occurs when there are 160 units, replacing we have:

p (x) = 100 * 160 - 20 * 160 - 0.25 * 160 ^ 2

p (x) = 6400

that is to say that the $ 6400 is the maximum profit.

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An equation that defines y as a function of x is given. Solve for y in terms of x, and replace y with the function notation f(x)
34kurt

Answer:C

Step-by-step explanation:

3 0
4 years ago
Points F(3, 3), K(6, 5), J(8, 2) and L(5, 0) lie in a coordinate plane. Which lines are perpendicular?
Romashka-Z-Leto [24]
To determine if a line is perpendicular to another, you must first determine the slope...
m = y1-y2/x1-x2
m of FK = 3-5/3-6 = -2/-3 = 2/3
m of FJ = 3-2/3-8 = 1/-5
m of FL = 3-0/3-5 = 3/-2
m of KJ = 5-2/6-8 = 3/-2
m of KL = 5-0/6-5 = 5
m of JL = 2-0/ 8-5 = 2/3

In order for two lines to be perpendicular, their slopes must be opposite reciprocals...
FK is perpendicular to FL
FK is perpendicular to KJ
JL is perpendicular to FL
JL is perpendicular to KJ
FJ is perpendicular to KL
8 0
4 years ago
You have $36,948.61 in a brokerage account, and you plan to deposit an additional $3,000 at the end of every future year until y
Luba_88 [7]
Current amount in account
P=36948.61

Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n

Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11

We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000

We can solve this by trial and error.


The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000.  It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.

So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.

So it takes 15.00 years to reach the goal of 280000 years.
8 0
3 years ago
A stadium has 48,000 seats. Seats sell for ​$25 in Section​ A, ​$20 in Section​ B, and ​$15 in Section C. The number of seats in
Ira Lisetskai [31]
I had a super-ugly equation that didn’t work, but it got me close. (24,000/12,000/12,000 or so)
Then I adjusted the numbers to make the money work.

I’m sorry I can’t help more.

24,000(25) + 14,200(20) + 9,800(15)
= 600,000 + 284,000 + 147,000 = 1,031,000

Section A = 24,000 seats
Section B = 14,200 seats
Section C = 9,800 seats

14,200 + 9,800 = 24,000 seats
5 0
3 years ago
What is the fourth law of exponents
fredd [130]

Answer:

The fourth law of exponents says that "any value other than zero brought to an exponent of zero is equal to one". ... However, zero to the zero gets an error with the calculator, thus any value other than zero brought to an exponent of zero is equal to one, this proves fourth law of exponents.

5 0
3 years ago
Read 2 more answers
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