(x - 1)(x - 2)(x + 2)
note that the sum of the coefficients 1 - 1 - 4 + 4 = 0
thus x = 1 is a root and (x - 1 ) is a factor
dividing x³ - x² - 4x + 4 by (x - 1)
x³ - x² - 4x + 4 = (x - 1)(x² - 4 ) (note (x² - 4 ) is a difference of squares )
x³ - x² - 4x + 4 = (x - 1)(x - 2)(x + 2)
(x - 1)(x - 2)(x + 2 ) =0
x - 1 = 0 ⇒ x = 1
x - 2 = 0 ⇒ x = 2
x + 2 = 0 ⇒ x = - 2
solutions are x = 1 or x = ± 2
(6x6)x(6x6x6)=
(6x6x6x6x6)
((3x3x3)x(3x3x3)x(3x3x3)x(3x3x3))
try it on the calculator.
Answer:
2.2
Step-by-step explanation:
I did it on khan
Answer: X=3
Step-by-step explanation:
Answer:
The 53rd term of this arithmetic sequence is -805.
Step-by-step explanation:
The general rule of an arithmetic sequence is the following:

In which d is the common diference between each term, that is,
.
To find the nth term of the sequence, this equation can be written as:

27,11, -5
So ![a_{1} = 27, a_{2} - a_{1} = 11 - 27 = -16[/tex[tex]a_{n} = a_{1} + (n-1)d](https://tex.z-dn.net/?f=a_%7B1%7D%20%3D%2027%2C%20a_%7B2%7D%20-%20a_%7B1%7D%20%3D%2011%20-%2027%20%3D%20-16%5B%2Ftex%3C%2Fp%3E%3Cp%3E%5Btex%5Da_%7Bn%7D%20%3D%20a_%7B1%7D%20%2B%20%28n-1%29d)

The 53rd term of this arithmetic sequence is -805.