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3 years ago

HELP ASAP !!!!! Write a direct variation equation that relates 16 and 2

Mathematics

2 answers:

Alinara [238K]3 years ago

6 0

Answer:

8×2-16

Step-by-step explanation:

if 8 is doubled or times by 2 it's permanent answer is really 16

creativ13 [48]3 years ago

6 0

Answer: 16 = 2x

Step-by-step explanation:

The pattern for a direct variation equation is y = kx.

y is the "output" or result.

k is the "constant" a number that will remain the same.

x is the "unknown" or variable that will make the output correct once found.

Here, x = 8

16 = 2(8)

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3 years ago

Which of the following options is a root of the function? f(x) = (3x + 5) (x2 - 6x + 9)2

Alika [10]

Answer:

The roots of the function are x = -5/3 and 3. Select these.

Step-by-step explanation:

The roots of the function are the solutions to the function. They are also called the x-intercepts or zeros. To find them, factor the function completely and solve using the zero product property.

f(x) = (3x+5)(x2-6x+9)2 becomes f(x) = (3x+5)(x-3)^2

Set each factor equal to 0 and solve for x.

(3x+5)=0

3x = -5

x = -5/3

(x-3)^2 = 0

x - 3=0

x = 3

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3 years ago

Which is true about the solution to the system of inequalities shown? y < x – 1 y < x – 3 All values that satisfy y < x

Masteriza [31]

<span>solution of a system of linear equations</span>

7 0

3 years ago

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What numbers are zeros of g(x) = x^2 - 2x - 4? take your time if you need to!

ipn [44]

Answer:

$x = 1 + \sqrt5, x = 1 - \sqrt5$

Step-by-step explanation:

Hello!

We can solve the quadratic by using the quadratic formula.

Standard form of a quadratic: $ax^2 + bx + c = 0$

Quadratic Formula: $x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$

Given our Equation: $g(x) = x^2 - 2x - 4$

a = 1
b = -2
c = -4

Plug the values into the equation and solve.

<h3>Solve</h3>

$x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$
$x = \frac{-(-2)\pm\sqrt{(-2)^2 - 4(1)(-4)}}{2(1)}$
$x = \frac{2\pm\sqrt{4 +16}}{2}$
$x = \frac{2\pm\sqrt{20}}{2}$
$x = \frac{2\pm\sqrt{4 * 5}}{2}$
$x = \frac{2\pm(\sqrt4 * \sqrt5)}{2}$
$x = \frac{2\pm2\sqrt5}{2}$
$x = 1 + \sqrt5, x = 1 - \sqrt5$

7 0

2 years ago

What is the solution of c² + 9 = 9

Lisa [10]

Answer:

The answer is 0

Step-by-step explanation:

0^2 is just 0x1 so 0+9=9

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2 years ago

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