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Dovator [93]
2 years ago
14

Please help!! Its a review and i need at least a 90!!

Mathematics
1 answer:
ANEK [815]2 years ago
4 0

Answer:

What grade is this.

Step-by-step explanation:

I think its the 3rd one

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Bobby is 12 years old. His age is nine
KatRina [158]

Answer:

65 because 12 plus 9 is 21 then 3 times 21 is 65

4 0
2 years ago
Find the equation of the line perpendicular to y=−2 that passes through the point (4, −2).
vfiekz [6]

Answer:

x = 4

Step-by-step explanation:

y = - 2 is the equation of a horizontal line parallel to the x- axis.

A perpendicular line is therefore a vertical line parallel to the y- axis with equation

x = c

where c is the value of the x- coordinates the line passes through.

The line passes through (4, - 2 ) with x- coordinate 4 , thus

x = 4 ← equation of perpendicular line

5 0
3 years ago
10 POINTS AND BRAINLIEST! PLEASE ANSWER BOTH QUESTIONS!
jok3333 [9.3K]

Segment CF is parallel to segment BE because these segments are side by side and will have the same distance continuously between them. Therefore your answer would be,

Segment BE

∠AOF is the angle that is the supplementary angle to ∠FOD because these are two angles that sum up to 180°. hence, the answer is,

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8 0
3 years ago
If the ratio of corresponding segments is 2:3, then the ratios of the areas and volumes are
kobusy [5.1K]

Answer:

4:9

Step-by-step explanation:

Area is squaring and Volume is cubing

So it'd be 2^2:3^3, or 4:9

I hope this helped and have a good rest of your day!

6 0
3 years ago
Use spherical coordinates. evaluate xyz dv e , where e lies between the spheres ρ = 4 and ρ = 6 and above the cone ϕ = π/3.
sergey [27]

Set

x=\rho\cos\theta\sin\varphi

y=\rho\sin\theta\sin\varphi

z=\rho\cos\varphi

so that the volume element is

\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

The integral is then

\displaystyle\iiint_Exyz\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi/3}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=4}^{\rho=6}\rho^5\cos\theta\sin\theta\sin^3\varphi\cos\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\rho

=\displaystyle\left(\int_0^{\pi/3}\sin^3\varphi\cos\varphi\,\mathrm d\varphi\right)\underbrace{\left(\int_0^{2\pi}\cos\theta\sin\theta\,\mathrm d\theta\right)}_0\left(\int_4^6\rho^5\,\mathrm d\rho\right)

and so evaluates to 0.

3 0
3 years ago
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