We know that
in a unit circle the radius is 1
therefore
[Length of a circumference]=2*pi*r------> 2*pi
if 2pi radians in a circle unit has a length of ------------> 2*pi
2pi/3 radians----------------------------> X
X=2pi/3
the answer is 2pi/3
I'm not sure how to display a graph on here, so I'm afraid I can't help you with that part.
However, the answer is C. (-2,3).
To create the graph, either put it into a graphing calculator or manually graph the equations by plugging in different numbers to the equation.
Answer:
c. -x + 3x + 7 = 2x+7
Step-by-step explanation:
f(x) = 3x +1 and g(x) = x - 6
f-g = 3x +1 - ( x - 6)
Distribute the minus sign
= 3x+1 - x+6
= 2x +7
Answer:
Step-by-step explanation:
Hello!
Given the probabilities:
P(A₁)= 0.35
P(A₂)= 0.50
P(A₁∩A₂)= 0
P(BIA₁)= 0.20
P(BIA₂)= 0.05
a)
Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)
Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.
b)
Considering that
you can clear the intersection from the formula
and apply it for the given events:


c)
The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:
P(B)= (A₁∩B) + P(A₂∩B)= 0.07 + 0.025= 0.095
d)
The Bayes' theorem states that:

Then:


I hope it helps!