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2 years ago

Dakota has g gumballs. Regan has 15 fewer gumballs than Dakota. Choose the expression that shows how many gumballs Regan has.

Mathematics

2 answers:

butalik [34]2 years ago

4 0

Answer:

G - 15

-by-step explanation:

Tanya [424]2 years ago

3 0

G - 15

I hope this helps tbh idk

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What is the correct factorization of 5!?

Oksi-84 [34.3K]

Answer:

B) 5 x 4 x 3 x 2 x 1

Step-by-step explanation:

When you see a ! directly next to a number (such as 5!), it means that you are multiplying starting from that number, and stepping down each time:

5! = 5 * 4 * 3 * 2 * 1

For example, take factoral 10: 10!

10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 3,628,800

In this case, you are multiplying 5!.

5! = 5 * 4 * 3 * 2 * 1 = (20) * (6) * 1 = 120

5! = 120

4 0

3 years ago

(please help quickly) Find the least common multiple of the following numbers.

IrinaK [193]

Answer:

1a. 156

1b. 147

2a. 45

2b. 84

3a. 160

3b. 108

4a. 210

4b.132

7 0

2 years ago

−3x + 2 ≥−1 in a number line

Ksivusya [100]

Answer:

Given, 3x−2<2x+1

⇒3x−2x<1+2

⇒x<3orx∈(−∞,3)

The lines y=3x−2 and y=2x+1 both will intersect at x=3

Clearly, the dark line shows the solution of 3x−2<2x+1.

Step-by-step explanation:

4 0

2 years ago

The national average for the math portion of the College Board’s Scholastic Aptitude Test

Alex73 [517]

Answer:

a) 0.1587

b) 0.023

c) 0.341

d) 0.818

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 515

Standard Deviation, σ = 100

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(score greater than 615)

P(x > 615)

$P( x > 615) = P( z > \displaystyle\frac{615 - 515}{100}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 615) = 1 - 0.8413 = 0.1587 = 15.87\%$

b) b) P(score greater than 715)

$P(x > 715) = P(z > \displaystyle\frac{715-515}{100}) = P(z > 2)\\\\P( z > 2) = 1 - P(z \leq 2)$

Calculating the value from the standard normal table we have,

$1 - 0.977 = 0.023 = 2.3\%\\P( x > 715) = 2.3\%$

c) P(score between 415 and 515)

$P(415 \leq x \leq 515) = P(\displaystyle\frac{415 - 515}{100} \leq z \leq \displaystyle\frac{515-515}{100}) = P(-1 \leq z \leq 0)\\\\= P(z \leq 0) - P(z < -1)\\= 0.500 - 0.159 = 0.341 = 34.1\%$

$P(415 \leq x \leq 515) = 34.1\%$

d) P(score between 315 and 615)

$P(315 \leq x \leq 615) = P(\displaystyle\frac{315 - 515}{100} \leq z \leq \displaystyle\frac{615-515}{100}) = P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.841 - 0.023 = 0.818 = 81.8\%$

$P(315 \leq x \leq 615) = 81.8\%$

4 0

3 years ago

Is -9 a rational number?<br> yes<br> no

Harlamova29_29 [7]

Answer:

Yes

Step-by-step explanation:

-9 is a rational number

5 0

3 years ago

Read 2 more answers