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3 years ago

The speed of an object changes only when it is acted on by an unbalanced force.

Physics

1 answer:

Nikitich [7]3 years ago

6 0

Answer:

If an object has a net force acting on it, it will accelerate. The object will speed up, slow down or change direction. An unbalanced force (net force) acting on an object changes its speed and/or direction of motion. An unbalanced force is an unopposed force that causes a change in motion.

Explanation:

I hope this helps you out and if your feeling generous plz mark brainliest it helps me a lot thank you:)

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A 0.40 kg ball is suspended from a spring with spring constant 12 n/m . part a if the ball is pulled down 0.20 m from the equili

PolarNik [594]

The total mechanical energy of the system at any time t is the sum of the kinetic energy of motion of the ball and the elastic potential energy stored in the spring:
$E=K+U= \frac{1}{2}mv^2+ \frac{1}{2}kx^2$
where m is the mass of the ball, v its speed, k the spring constant and x the displacement of the spring with respect its rest position.

Since it is a harmonic motion, kinetic energy is continuously converted into elastic potential energy and vice-versa.

When the spring is at its maximum displacement, the elastic potential energy is maximum (because the displacement x is maximum) while the kinetic energy is zero (because the velocity of the ball is zero), so in this situation we have:
$E=U_{max}= \frac{1}{2}k(x_{max})^2$

Instead, when the spring crosses its rest position, the elastic potential energy is zero (because x=0) and therefore the kinetic energy is at maximum (and so, the ball is at its maximum speed):
$E=K_{max}= \frac{1}{2}m(v_{max})^2$

Since the total energy E is always conserved, the maximum elastic potential energy should be equal to the maximum kinetic energy, and so we can find the value of the maximum speed of the ball:
$U_{max}=K_{max}$
$\frac{1}{2}k(x_{max})^2 = \frac{1}{2}m(v_{max})^2$
$v_{max}= \sqrt{ \frac{k x_{max}^2}{m} }= \sqrt{ \frac{(12 N/m)(0.20 m)^2}{0.4 kg} }=1.1 m/s$

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3 years ago

In the paralleling technique, the central ray of the x-ray beam must be _____ to the film sensor and the long axis of the tooth.

Wittaler [7]

The film sensor and the long axis of the tooth must be aligned perpendicular to the central ray of the x-ray beam when using the paralleling approach.

To find the answer, we need to know above the paralleling technique in the dental x-ray.

<h3>What is paralleling technique?</h3>

The paralleling technique is the most dependable method for capturing periapical x-rays because it produces high-quality images with little distortion.
The central x-ray beam should be pointed perpendicular to the long axis of the tooth in issue, and the film should be positioned parallel to it.

The paralleling technique is the most dependable method for capturing periapical x-rays because it produces high-quality images with little distortion.

The central x-ray beam should be pointed perpendicular to the long axis of the tooth in issue, and the film should be positioned parallel to it.

When preparing for an x-ray, it is imperative to keep in mind the root anatomy.

The maxillary occlusal plane of the patient should also be parallel to the ground.

Thus, we can conclude that, the film sensor and the long axis of the tooth must be aligned perpendicular to the central ray of the x-ray beam when using the paralleling approach.

Learn more about paralleling technique here:

brainly.com/question/28120540

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mark me brainliestt :))

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goldfiish [28.3K]

Explanation:

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