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Bas_tet [7]
3 years ago
10

What is the kinetic energy of a 0.25kg ball rolling at a speed of 2.5m/s

Physics
1 answer:
Lisa [10]3 years ago
4 0

Answer:

Explanation:

Kinetic Energy formula:

KE = \frac{1}{2}mv²

m=mass

v=speed

Given:

m=0.25kg

v=2.5m/s

Plug the values in:

KE = 1/2(0.25kg)(2.5m/s)²

KE = 0.78125 J (Joules)

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Find the magnitude of the angular momentum of the second hand on a clock about an axis through the center of the clock face. Ass
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Answer:

L = 4.711 *10^{-6} kg m2/s

Explanation:

i =\frac{ml^3}{3}

= \frac{0.00*.15^2}{3}

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angular velocity

\omega = \frac{2\pi}{60}

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the angular momentum,

L = I\omega

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3 0
3 years ago
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A beam of light has a wavelength of 650 nm in vacuum. (a) What is the speed of this light in a liquid whose index of refraction
Lady_Fox [76]

Answer:

The speed of this light and wavelength in a liquid are 2.04\times10^{8}\ m/s and 442 nm.

Explanation:

Given that,

Wavelength = 650 nm

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Using formula of speed

n = \dfrac{c}{v}

Where, n = refraction index

c = speed of light in vacuum

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Put the value into the formula

1.47=\dfrac{3\times10^{8}}{v}

v=\dfrac{3\times10^{8}}{1.47}

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(b). We need to calculate the wavelength

Using formula of wavelength

n=\dfrac{\lambda_{0}}{\lambda}

\lambda=\dfrac{\lambda_{0}}{n}

Where, \lambda_{0} = wavelength in vacuum

\lambda = wavelength in medium

Put the value into the formula

\lambda=\dfrac{650\times10^{-9}}{1.47}

\lambda=442\times10^{-9}\ m

Hence, The speed of this light and wavelength in a liquid are 2.04\times10^{8}\ m/s and 442 nm.

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