F= Force
M=Mass
A= acceleration
F=N
Mass= in grams or kilo grams (mostly kg)
A= m/s
Answer:
in 90 seconds It'll travel 450m At constant speed of 5m/s
Answer:
Acceleration = 0.9144 m/s^2
Explanation:
Initial speed = 45 ft/s
Final speed = 60 ft/s
Time = 5 sec
Acceleration = a = (v-u) / t
= 60-45 / 5
= 0.9144 m/s^2
Answer:
ΔU = 5.21 × 10^(10) J
Explanation:
We are given;
Mass of object; m = 1040 kg
To solve this, we will use the formula for potential energy which is;
U = -GMm/r
But we are told we want to move the object from the Earth's surface to an altitude four times the Earth's radius.
Thus;
ΔU = -GMm((1/r_f) - (1/r_i))
Where;
M is mass of earth = 5.98 × 10^(24) kg
r_f is final radius
r_i is initial radius
G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²
Since, it's moving to altitude four times the Earth's radius, it means that;
r_i = R_e
r_f = R_e + 4R_e = 5R_e
Where R_e is radius of earth = 6371 × 10³ m
Thus;
ΔU = -6.67 × 10^(-11) × 5.98 × 10^(24)
× 1040((1/(5 × 6371 × 10³)) - (1/(6371 × 10³))
ΔU = 5.21 × 10^(10) J
Answer:
4.3 m/s
Explanation:
Using conservation of momentum, assume that the collision is elastic and that the 3.0 g ball stuck with the carton
3.0 g = 3 / 1000 = 0.003 kg = m₁
40 g = 40 / 1000 = 0.04 kg = m₂, u₂ = 0 since the body is stationary and v = 0.3m/s
m₁u₁ + m₂u₂ = v ( m₁ + m₂)
0.003 u₁ = 0.30 ( 0.003 + 0.04) = 0.0129
u₁ = 0.0129 / 0.003 = 4.3 m/s
