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Mashutka [201]
4 years ago
14

A right prism has height 8 and triangular bases with sides of length 7, 8, and 9. What is the: Volume of the prism?

Mathematics
2 answers:
Alex Ar [27]4 years ago
6 0

Volume of the prism = Area of the cross section × Height of the prism

Artyom0805 [142]4 years ago
5 0

Step-by-step explanation:

Volume of the prism = Area of the cross section × Height of the prism

V=( 1/2 × Base of the triangle × Perpendicular height of the triangle) × Height of the prism

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What is the answer to - 1/3 (x+6)=0
Sauron [17]
(-\frac{1}{3})(x+6)=0\\\\\frac{1}{3}(x+6)*3=0*3\\\\-1(x+6)=0\\\\-(x+6)*-1=0*-1\\\\x+6=0\\\\x=-6
3 0
4 years ago
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How do you solve st+3t=6
bonufazy [111]
You will factor out the common factor of t if you are solving for t. you will then divide both sides by (s+3) to make t the subject of the formula. for this question you can only get t in terms of s.
so:
st+3t=6
t(s+3)/(s+3)=6/(s+3)
t=6/(s+3)

if you are required to solve for s then you are going to subtract 3t from both sides. you can factorise 6-3t .you will then divide both sides by t to isolate s.for this question you can only get s in terms of t.so:

st+3t-3t=6-3t
st/t=2(3-t)/t
s=2(3-t)/t
4 0
3 years ago
Find csc x if sin x + cot x cos x =√3.
Oksi-84 [34.3K]

Answer:

The answer is (d) ⇒ cscx = √3

Step-by-step explanation:

∵ sinx + (cotx)(cosx) = √3

∵ sinx + (cosx/sinx)(cosx) = √3

∴ sinx + cos²x/sinx = √3

∵ cos²x = 1 - sin²x

∴ sinx + (1 - sin²x)/sinx = √3 ⇒ make L.C.M

∴ (sin²x + 1 - sin²x)/sinx = √3

∴ 1/sinx = √3

∵ 1/sinx = cscx

∴ cscx = √3

7 0
3 years ago
Identify the mapping diagram that represents the relation and determine whether the relation is a function. {(–8, –6), (–5, 2),
SashulF [63]
Do you have the answer options? Sorry, can't answer without them ):
8 0
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The head of a computer science department is interested in estimating the proportion of students entering the department who wil
olya-2409 [2.1K]

Answer:

96

Step-by-step explanation:

From the given information:

At 95% Confidence interval level,Level of significance \alpha 0.05, the value of Z from the standard normal tables = 1.96

Margin of Error = 0.10

Let assume that the estimated proportion = 0.5

therefore; the sample size n can be determined by using the formula: n =(\dfrac{Z}{E})^2 \times p\times (1-p)

n =(\dfrac{1.96}{0.1})^2 \times 0.5\times (1-0.5)

n =(19.6)^2 \times 0.5\times (0.5)

n = 96.04

n \approx 96

8 0
3 years ago
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