Answer:
<em>a) 8.33 x </em><em> Pa or 8.22 x </em><em> atm</em>
<em>b) 1.66 x </em><em> Pa or 1.63 x </em><em> atm</em>
<em>c) </em> <em>2.77 x </em><em> kg/m^2-s</em>
<em></em>
Explanation:
Intensity of light = 2500 W/m^2
area = 25 ft^2
a) average radiation pressure on a totally absorbing section of the floor
where I is the intensity of the light
c is the speed of light =
= <em>8.33 x </em><em> Pa</em>
1 pa =
8.33 x Pa = <em>8.22 x </em><em> atm</em>
<em></em>
b) average radiation for a totally radiating section of the floor
this means that the pressure for a totally radiating section is twice the average pressure of the totally absorbing section
therefore,
Pav = 2 x 8.33 x = <em>1.66 x </em><em> Pa</em>
or
Pav in atm = 2 x 8.22 x =<em> 1.63 x </em><em> atm</em>
<em></em>
c) average momentum per unit volume is
= <em>2.77 x </em><em> kg/m^2-s</em>