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Alex Ar [27]
4 years ago
13

In the 25 ftft Space Simulator facility at NASA's Jet Propulsion Laboratory, a bank of overhead arc lamps can produce light of i

ntensity 2500 W/m^2 at the floor of the facility. (This simulates the intensity of sunlight near the planet Venus.)
Required:
Find the average radiation pressure (in pascals and in atmospheres) on

a. A totally absorbing section of the floor.
b. A totally reflecting section of the floor.
c. Find the average momentum density (momentum per unit volume) in the light at the floor.
Physics
1 answer:
nika2105 [10]4 years ago
5 0

Answer:

<em>a) 8.33 x </em>10^{-6}<em> Pa  or  8.22 x </em>10^{-11}<em> atm</em>

<em>b) 1.66 x </em>10^{-5}<em> Pa  or  1.63 x </em>10^{-10}<em> atm</em>

<em>c) </em> <em>2.77 x </em>10^{-14}<em> kg/m^2-s</em>

<em></em>

Explanation:

Intensity of light = 2500 W/m^2

area = 25 ft^2

a) average radiation pressure on a totally absorbing section of the floorPav = \frac{I}{c}

where I is the intensity of the light

c is the speed of light = 3*10^{8} m/s

Pav = \frac{2500}{3*10^{8} } = <em>8.33 x </em>10^{-6}<em> Pa</em>

1 pa = 9.87*10^{-6}

8.33 x 10^{-6} Pa = <em>8.22 x </em>10^{-11}<em> atm</em>

<em></em>

b) average radiation for a totally radiating section of the floor

Pav = \frac{2I}{c}

this means that the pressure for a totally radiating section is twice the average pressure of the totally absorbing section

therefore,

Pav = 2 x 8.33 x 10^{-6}  = <em>1.66 x </em>10^{-5}<em> Pa</em>

or

Pav in atm = 2 x 8.22 x 10^{-11} =<em> 1.63 x </em>10^{-10}<em> atm</em>

<em></em>

c) average momentum per unit volume is

m = \frac{I}{c^{2} }

m = \frac{2500}{(3*10^{8}) ^{2} } = <em>2.77 x </em>10^{-14}<em> kg/m^2-s</em>

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