Answer: 10 m/s
Given:
Force, F = 25 N
Initial velocity
Distance moved, s= 4 m
mass, m = 2 kg
Formula Used:
where a is the acceleration.
equation of motion:
First, we would calculate the acceleration from the formula for force.
Using the equation of motion, we can find the final velocity now:
××
taking the square root on both sides and ignoring the negative sign:
v= 10 m/s
Answer:
v = 120 m/s
Explanation:
We are given;
earth's radius; r = 6.37 × 10^(6) m
Angular speed; ω = 2π/(24 × 3600) = 7.27 × 10^(-5) rad/s
Now, we want to find the speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator.
The angle will be;
θ = ¾ × 90
θ = 67.5
¾ is multiplied by 90° because the angular distance from the pole is 90 degrees.
The speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator will be:
v = r(cos θ) × ω
v = 6.37 × 10^(6) × cos 67.5 × 7.27 × 10^(-5)
v = 117.22 m/s
Approximation to 2 sig. figures gives;
v = 120 m/s
Answer: a= 37m
Explanation: V= 15 m/s (Velocity) t= 0.41s (time) formula: a= v/t
15 m/s / 0.41 (15 divided by 0.41) = 36.583m
There are 2 significant digits, 36, you look at the third digit, either round up or down in this case up to 36. a= 37m
Answer:
around 12 seconds
Explanation:
The speed of gravity is 9.8 meters per second. If you divide 116 by 9.8, you would get 11.8367346939 seconds. To keep it simple, I rounded up to 12 seconds.