All categories

2 years ago

What is the relationship between the speed of an object and its kinetic energy?

Physics

2 answers:

VladimirAG [237]2 years ago

5 0

Answer:

For the purposes of your question, we can think of speed and velocity as being the same thing. Therefore, the kinetic energy of an object is proportional to the square of its velocity (speed). In other words, If there is a twofold increase in speed, the kinetic energy will increase by a factor of four.

Explanation:

Helga [31]2 years ago

5 0

The kinetic energy of an object is directly proportional to the square of the speed of the object.

Explanation: 

The kinetic energy is the measure of energy exerted by the object during its state of motion. The kinetic energy depend on the mass of the object and the speed the object is moving. So, the kinetic energy is related to square of the speed of the object.

$\text { Kinetic energy }=\frac{1}{2} \times \text { mass of the object } \times \text { (velocity of the object) }^{2}$

Thus, kinetic energy is directly proportional to the square of the speed of the object. So, as the speed of the object increases the kinetic energy increases double the times of its speed of the object.

You might be interested in

3. A 2kg wooden block whose initial speed is 3 m/s slides on a smooth floor for 2 meters before it comes to a

serious [3.7K]

Answer:

Calculating Coefficient of friction is 0.229.

Force is 4.5 N that keep the block moving at a constant speed.

Explanation:

We know that speed expression is as $\mathrm{V}^{2}=\mathrm{V}_{\mathrm{i}}^{2}+2 . \mathrm{a} . \Delta \mathrm{s}$ .

Where, ${V}_{i}$ is initial speed, V is final speed, ∆s displacement and a acceleration.

Given that,

${V}_{i}$ =3 m/s, V = 0 m/s, and ∆s = 2 m

Substitute the values in the above formula,

$0=3^{2}-2 \times 2 \times a$

0 = 9 - 4a

4a = 9

$a=2.25 \mathrm{m} / \mathrm{s}^{2}$

$a=2.25 \mathrm{m} / \mathrm{s}^{2}$ is the acceleration.

Calculating Coefficient of friction:

$\mathrm{F}=\mathrm{m} \times \mathrm{a}$

$\mathrm{F}=\mu \times \mathrm{m} \times \mathrm{g}$

Compare the above equation

$\mu \times m \times g=m \times a$

Cancel "m" common term in both L.H.S and R.H.S

$\text { Equation becomes, } \mu \times g=a$

$\text { Coefficient of friction } \mu=\frac{a}{g}$

$\mathrm{g} \text { on earth surface }=9.8 \mathrm{m} / \mathrm{s}^{2}$

$\mu=\frac{2.25}{9.8}$

$\mu=0.229$

Hence coefficient of friction is 0.229.

calculating force:

$\text { We know that } \mathrm{F}=\mathrm{m} \times \mathrm{a}$

$\mathrm{F}=2 \times 2.25 \quad(\mathrm{m}=2 \mathrm{kg} \text { given })$

F = 4.5 N

Therefore, the force would be 4.5 N to keep the block moving at a constant speed across the floor.

7 0

2 years ago

What does keplers second law of planetary monition imply

Gemiola [76]

Kepler's second law of planetary motion describes the speed of a planet traveling in an elliptical orbit around the sun. It states that a line between the sun and the planetsweeps equal areas in equal times. Thus, the speed of theplanet increases as it nears the sun and decreases as it recedes from the sun.

6 0

2 years ago

Read 2 more answers

If 105 J of energy is used in 103 s, what is the average power consumption in watts?

jekas [21]

Power = work/time

P = 105J/103s

P = 1.019 watts

4 0

2 years ago

Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 1.80 cm from the axis to equal

Arturiano [62]

Answer:

The required angular speed ω of an ultra-centrifuge is:

ω = 18074 rad/sec

Explanation:

Given that:

Radius = r = 1.8 cm

Acceleration due to g = a = 6.0 x 10⁵ g

Sol:

We know that

Angular Acceleration = Angular Radius x Speed²

a = r x ω ²

Putting the values

6 x 10⁵ g = 1.8 cm x ω ²

Converting 1.8 cm to 0.018 m, also g = 9.8 ms⁻²

6 x 10⁵ x 9.8 = 0.018 x ω ²

ω ² = (6 x 10⁵ x 9.8) / 0.018

ω ² = 5880000 / 0.018

ω ² = 326666667

ω = 18074 rad/sec

7 0

2 years ago

Which is a derived unit? a.) kilogram b.) joule c.) micrometer d.) millimeter

Dovator [93]

Joule us a derived unit

5 0

3 years ago

Read 2 more answers