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JulsSmile [24]
3 years ago
6

What is the relationship between the speed of an object and its kinetic energy?

Physics
2 answers:
VladimirAG [237]3 years ago
5 0

Answer:

For the purposes of your question, we can think of speed and velocity as being the same thing. Therefore, the kinetic energy of an object is proportional to the square of its velocity (speed). In other words, If there is a twofold increase in speed, the kinetic energy will increase by a factor of four.

Explanation:

Helga [31]3 years ago
5 0

The kinetic energy of an object is directly proportional to the square of the speed of the object.

<u>Explanation: </u>

The kinetic energy is the measure of energy exerted by the object during its state of motion. The kinetic energy depend on the mass of the object and the speed the object is moving. So, the kinetic energy is related to square of the speed of the object.

       \text { Kinetic energy }=\frac{1}{2} \times \text { mass of the object } \times \text { (velocity of the object) }^{2}

Thus, kinetic energy is directly proportional to the square of the speed of the object. So, as the speed of the object increases the kinetic energy increases double the times of its speed of the object.

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An astronaut on the moon places a package on a scale and finds its weight to be 10. N. () What would the weight of the package
jeka94

Answer:

(a) 61.25 N

(b) 6.25 kg

(c) 6.25 Kg

Explanation:

Weight on moon = 10 N

Acceleration due to gravity on moon = 1.6 m/s^2

Acceleration due to gravity on earth = 9.8 m/s^2

Let m be the mass of the package.

(a) Weight on earth = mass x acceleration due to gravity on earth

Weight on earth = 6.25 x 9.8 = 61.25 N

(b) Weight on moon = mass x acceleration due to gravity on moon

10 = m x 1.6

m = 6.25 kg

(c) Mass of the package remains same as mass does not change, so the mass of package on earth is 6.25 kg.

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A 40-cmcm-long tube has a 40-cmcm-long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. A
Licemer1 [7]

Answer:

1070 Hz

Explanation:

First, I should point out there might be a typo in the question or the question has inconsistent values. If the tube is 40 cm long, standing waves cannot be produced at 42.5 cm and 58.5 cm lengths. I assume the length is more than the value in the question then. Under this assumption, we proceed as below:

The insert in the tube creates a closed pipe with one end open and the other closed. For a closed pipe, the difference between successive resonances is a half wavelength \frac{\lambda}{2}.

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\dfrac{\lambda}{2}=58.5-42.5=16 \text{ cm}

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