Question

The position of a particle moving on x-axis is given by x(t)=t^2 + 2, it’s average velocity in the final interval from t=1 to t=2 is :

Answer 1

Answer:

The average velocity is 2 m/s.

Explanation:

The velocity of the particle is the time derivative of its position $x(t):$

$v =\frac{dx(t)}{dt} = \frac{d}{dt}[t^2+2]$

$v =2t$

Now the average from $t=1$ and $t=2$ is

$v_{avg} = \dfrac{v(2)-v(1)}{2-1} = \dfrac{2(2)-2(1)}{1}$

$\boxed{v_{avg} = 2 m/s} \text{ ( If the units are m/s)}$

Thus, the average velocity is 2 m/s.