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MrRa [10]
3 years ago
6

A 2.0 kg rock is dropped from a height of 125 m. What is the momentum of the object just before it strikes the ground (Use g=10

m/s2)?
Physics
2 answers:
Maslowich3 years ago
8 0

Answer:

5,000 kg-m/s going south

Explanation:

Since you're only given mass and height, not velocity. You have to find velocity first. The equation for velocity is v=2gh. We know gravity is 10 since it's given & height is also given which is 125m. After doing the math, it's 2,500. Now that you have velocity, you can plug velocity into the formula for momentum which is p=mv. 2.0 times 2,500 = 5,000 kg-m/s going south.

goldenfox [79]3 years ago
4 0

Answer:

100Ns

Explanation:

find velocity and then plug into momentum formula momentum=(velocity)(mass)

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calculating displacement.

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2 years ago
A spring is characterized by a spring constant of 60 N/m. How much potential energy does it store, when stretched by 1.0 cm?
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Answer:

3.0 x10^-3 J

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The potential energy of a spring is given by PE = (0.5)k*x^2  

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3 years ago
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What is the maximum speed when the conditions are mass =450 kg, initial height= 30 m, and the roller coaster is initially at res
Zarrin [17]

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B. 24.2 m/s

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P.E_{max} = mgh\\\\PE_{max} = 450 *9.8*30\\\\PE_{max} = 132,300 \ J

P.E_{max} = K.E_{max} \ (law \ of \ conservation\ of \ energy)

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Therefore, the maximum speed of the roller coaster is 24.2 m/s.

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