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MrRa [10]
3 years ago
6

A 2.0 kg rock is dropped from a height of 125 m. What is the momentum of the object just before it strikes the ground (Use g=10

m/s2)?
Physics
2 answers:
Maslowich3 years ago
8 0

Answer:

5,000 kg-m/s going south

Explanation:

Since you're only given mass and height, not velocity. You have to find velocity first. The equation for velocity is v=2gh. We know gravity is 10 since it's given & height is also given which is 125m. After doing the math, it's 2,500. Now that you have velocity, you can plug velocity into the formula for momentum which is p=mv. 2.0 times 2,500 = 5,000 kg-m/s going south.

goldenfox [79]3 years ago
4 0

Answer:

100Ns

Explanation:

find velocity and then plug into momentum formula momentum=(velocity)(mass)

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A tow truck drags a stalled car along a road. The chain makes an angle of 30???? with the road and the tension in the chain is 1
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Answer: work = 1,305kJ

Explanation:

angle= 30°

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an object of mass m is traveling at constant speed v in a circular path of radius r. how much work is done by the centripetal fo
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The work done is by the centripetal force on mass m during an angular displacement of 2π revolutions mv²2π /r J

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the centripetal force is given by

F= mv²/r       (equation1)

Work done is given by

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d = 2π

work is done by the centripetal force on mass m during an angular displacement of 2π revolutions is given by:

to calculate work done using equation 1 in 2  we get

W = mv² d/r

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The work done is by the centripetal force on mass m during an angular displacement of 2π revolutions mv²2π /r J

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