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guajiro [1.7K]
2 years ago
15

Low tides occur when a coastline is located within a tidal bulge.

Chemistry
2 answers:
poizon [28]2 years ago
5 0

the correct answer would be false. i got this correct on my test.

Viktor [21]2 years ago
4 0

Answer:The answer is false. Brainliest please

Explanation:

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Which property is better explained by the band theory than by the sea-of-electrons model?
Sonbull [250]
Luster is the correct answer.
8 0
2 years ago
What is the chemical formula for 8.6 mol of sulfur and 3.42 mol of phosphorus
adell [148]

The chemical formula for the compound containing 8.6 mol of sulfur and 3.42 mol of phosphorus is P₂S₅

<h3>How do I determine the formula of the compound?</h3>

From the question given above, the following data were obatined:

  • Sulphur (S) = 8.6 moles
  • Phosphorus (P) = 3.42 mole
  • Chemical formula =?

The chemical formula of the compound can be obtained as follow:

Divide by their molar mass

S = 8.6 / 32 = 0.26875

P = 3.42 / 31 = 0.11032

Divide by the smallest

S = 0.26875 / 0.11032 = 2.44

P = 0.11032 / 0.11032 = 1

Multiply by 2 to express in whole number

S = 2.44 × 2 = 5

P = 1 × 2 = 2

Thus, the chemical formula is P₂S₅

Learn more about empirical formula:

brainly.com/question/9459553

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5 0
1 year ago
How many moles of sodium cyanide (NaCN) would be needed to produce 4.2 moles of sodium sulfate (Na2SO4)? H2SO4 + 2NaCN → 2HCN +
leonid [27]
The purpose of a chemical equation is to relate the amounts of reactants to the amounts of products based on the rate each is consumed. In this problem, one mole of sulfuric acid is consumed along with two moles of sodium cyanide to produce two moles of hydrocyanic acid and one mole of sodium sulfate. The relationship between sodium cyanide and sodium sulfate is 2:1, meaning that two moles of NaCN is required to produce one mole of sodium sulfate.

To produce 4.2 moles of sodium sulfate, two times this amount of NaCN is required. This means that you would need 8.4 moles of sodium cyanide.

Hope this helps!
4 0
3 years ago
Read 2 more answers
the student records the concentration of the stock solution of H2O2 to be 0.950 M. The student proceeds to prepare the reaction
lana [24]

Answer:

0.0400M of KI

Explanation:

Molarity is an unit of concentration defined as the ratio between moles of solute and liters of solution.

When you add 10.0 mL of 0.10M KI and 15.0mL, total volume is:

25.0mL = <em>0.025L of solution</em>

<em />

And moles of KI are:

0.0100L × 0.10M = <em>0.00100 moles of KI</em>

<em />

Thus, molarity is:

0.00100 moles / 0.025L = <em>0.0400M of KI</em>

6 0
3 years ago
a = Proton transfer d = SN2 Nucleophilic substitution g = Nucleophilic subs at carbonyl(acyl Xfer) b = Lewis acid/base e= Electr
marissa [1.9K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The solution to this question is shown on the second uploaded image

Explanation:

4 0
3 years ago
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