Answer:
E = 15×10⁻²⁹ J
Explanation:
Given data:
Frequency of photon = 2.2× 10⁷ Hz
Energy of photon = ?
Solution:
Formula:
E = h.f
h = 6.63×10⁻³⁴ Js
by putting values,
E = 6.63×10⁻³⁴ Js × 2.2× 10⁷ s⁻¹
E = 14.586 ×10⁻²⁹ J
E = 15×10⁻²⁹ J
The energy of photon is 15×10⁻²⁹ J.
You will most lkely get better answers if you postb this under spanish
<u>5.6400 </u>is the mass of silver bromide that precipitates when 2.96 g of iron(iii) bromide is combined with excess silver nitrate.
<h3>
Difference between silver bromide and iron(iii) bromide</h3>
- Silver bromide (AgBr) is a soft, pale-yellow, water-insoluble salt well known (along with other silver halides) for its unusual sensitivity to light. This property has allowed silver halides to become the basis of modern photographic materials. AgBr is widely used in photographic films and is believed by some to have been used for making the Shroud of Turin. The salt can be found naturally as the mineral bromargyrite.
- Iron(III) bromide is the chemical compound with the formula FeBr3. Also known as ferric bromide, this red-brown odourless compound is used as a Lewis acid catalyst in the halogenation of aromatic compounds. It dissolves in water to give acidic solutions.
Learn more about Silver bromide
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Answer:
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Explanation:
I think its like radar or something like that- im not too sure sorry
Full electron configuration of barium: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6 6s2
