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Usimov [2.4K]
3 years ago
11

Lewis structure for nitrogen triiodide, NI(3)

Chemistry
1 answer:
Rasek [7]3 years ago
3 0

Answer:

Lewis structure for nitrogen triiodide,NI_3 is given in the attachment.

Explanation:

Given:

The given compound is Nitrogen triiodide. In which 1 atom of Nitrogen combines with 3 atoms of Iodine. Both Nitrogen and Iodine are non-metals,So they form covalent bond by sharing of electrons.

The electron configuration of Nitrogen and Iodine is given below;

N(7) = 1s^2,2s^22p^3\\I(53) = 1s^2,2s^22p^6,3s^23p^63d^{10},4s^24p^64d^{10},5s^25p^5

There are 5 electrons in valance shell of Nitrogen atom and 7 electrons in valance shell of Iodine atom.

So, 3 atom of Iodine shares 1 electron with 1 electrons of Nitrogen.

The Lewis dot Structure is in the attachment.

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Answer:

\large \boxed{\text{200 g CO}_{{2}}}

Explanation:

We will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

Mᵣ:                                 44.01

            C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O

n/mol:    1.5

1. Calculate the moles of CO₂

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\rm  \text{Moles of CO}_{2} = \text{1.5 mol C$_{3}$H}_{8} \times \dfrac{\text{3 mol CO}_{2}}{\text{1 mol C$_{3}$H}_{8}} =\text{4.5 mol CO}_{2}

2. Calculate the mass of CO₂.

\text{Mass of CO}_{2} = \text{4.5 mol CO}_{2}  \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO$_{2}$}} = \textbf{200 g CO}_{\mathbf{2}}\\\text{The reaction will form $\large \boxed{\textbf{200 g CO}_{\mathbf{2}}}$}

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