Answer:
27 min
Explanation:
By the Michaelis-Menten Kinetics Model, the initial velocity of the enzymatic reaction is given by:
where vmax is the maximum velocity, [S] is the substrate concentration and Km is the equilibrium constant. The maximum velocity is directly proportional to the enzyme concentration.
So, for 12μmol of the product formed in 9 min, the velocity is also:
v0 = 12/9 = 1.33 μmol/min
For [S] 1,000 times higher then Km, Km can be unconsidered in the equation, so:
v0 = vmax
vmax = 1.33 μmol/min
If the enzyme concentration decreases by three, the maximum velocity will also decrease by three, so it will be: 0.443μmol/min. Km continues the same, and [S] will be multiplied by 2, so Km can still be unconsidered. So:
v0 = vmax
v0 = 0.443 μmol/min
Then,
0.443 = 12/t
t = 12/0.443
t = 27 min
<span>6.38x10^-2 moles
First, let's determine how many moles of gas particles are in the two-liter container. The molar volume for 1 mole at 25C and 1 atmosphere is 24.465 liters/mole. So
2 L / 24.465 L/mol = 0.081749438 mol
Now air doesn't just consist of nitrogen. It also has oxygen, carbon dioxide, argon, water vapor, etc. and the total number of moles includes all of those other gasses. So let's multiply by the percentage of nitrogen in the atmosphere which is 78%
0.081749438 mol * 0.78 = 0.063764562 mol.
Rounding to 3 significant figures gives 6.38x10^-2 moles</span>
Answer:
49902.4 g/mol.
Explanation:
Using ideal gas equation,
PV = nRT
Where,
P = pressure
= 0.00144 atm
V = volume
= 0.01 l
T = absolute temperature
= 273 + 23.5
= 296.5 K
R = gas constant
= 0.0821 atm.l/K.mol
n = number of moles
n = (0.00144 * 0.01)/0.0821 * 296.5
= 5.92 x 10^-7 mol.
Molar mass = mass/number of moles
= 0.02952/5.92 x 10^-7
= 49902.4 g/mol.
Can you provide a picture