Answer:
the combining power of an element, especially as measured by the number of hydrogen atoms it can displace or combine with.
Explanation:
Ne is isoelectronic with Na+ ion.
Answer : The partial pressure of
and
are, 84 torr and 778 torr respectively.
Explanation : Given,
Mass of
= 15.0 g
Mass of
= 22.6 g
Molar mass of
= 197.4 g/mole
Molar mass of
= 32 g/mole
First we have to calculate the moles of
and
.

and,

Now we have to calculate the mole fraction of
and
.

and,

Now we have to partial pressure of
and
.
According to the Raoult's law,

where,
= partial pressure of gas
= total pressure of gas
= mole fraction of gas


and,


Therefore, the partial pressure of
and
are, 84 torr and 778 torr respectively.
<u>Given:</u>
Volume of Na2CO3 = 250 ml = 0.250 L
Molarity of Na2CO3 = 6.0 M
Volume of CaF2 = 750 ml = 0.750 L
Molarity of CaF2 = 1.0 M
<u>To determine:</u>
The mass of CaCO3 produced
<u>Explanation:</u>
Na2CO3 + CaF2 → CaCO3 + 2NaF
Based on the reaction stoichiometry:
1 mole of Na2CO3 reacts with 1 moles of Caf2 to produce 1 mole of caco3
Moles of Na2CO3 present = V * M = 0.250 L * 6.0 moles/L = 1.5 moles
Moles of CaF2 present = V* M = 0.750 * 1 = 0.750 moles
CaF2 is the limiting reagent
Thus, # moles of CaCO3 produced = 0.750 moles
Molar mass of CaCO3 = 100 g/mol
Mass of CaCO3 produced = 0.750 moles * 100 g/mol = 75 g
Ans: Mass of CaCO3 produced = 75 g
Pressure of the gas inside the container is 662.59 torr.
<h3>What is ideal gas law?</h3>
The ideal gas law (PV = nRT) connects the macroscopic characteristics of ideal gases. An ideal gas is one in which the particles are both non-repellent and non-attractive to one another (have no volume).
The general law of ideal gas can be applied here: PV is equal to nRT, where P is the gas pressure in atm.
V is the number of moles of the gas in a mole, and n is the volume of the gas in L. R is the universal gas constant. T is the temperature(Kelvin) of the gas.
If P and T are different values and n and V are constants, then
(P₁T₂) = (P₂T₁).
P₁ = 735 torr, T₁ = 29°C + 273 = 302 K,
P₂ = ??? torr, T₂ = 62°C + 273 = 335 K.
∴ P₂ = (P₁T₂)/(P₁) = (735 torr)(302 K)/(335 K) = 662.59 torr.
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