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2 years ago

9

Does Kinetic energy depend only on an object’s speed and velocity?

2 answers:

SSSSS [86.1K]2 years ago

6 0

Yes . kinetic energy mainly focuses on movement .

BaLLatris [955]2 years ago

4 0

yes .. . . . .. . . .. ....... . ..dlnv3r;'mw,c kc;oqc,

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Which of the following gases is the most abundant in a volcanic eruption?

expeople1 [14]

Option C: Sulfur Dioxide is the answer

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3 years ago

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Carbon 14 has a half-life of 5730 years. A geologist has dated a fossil sample, at roughly 28650 years. How much carbon 14 remai

IgorC [24]

<h3>Answer </h3>

After another 5730 years ( three half lives or 17190 years) 17.5 /2 = 8.75mg decays and 8.75g remains left. after three half lives or 17190 years, 8.75 g of C-14 will be

Explanation:

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2 years ago

Determine whether each of the following statements about sulfur oxide and/or nitrogen oxide pollution is true or false.

astraxan [27]

Answer:

a) False

b) False

c) True

Explanation:

a) Most sulfur oxides formed during combustion come from sulfur in the air: The sulfur burns in presence of oxygen to produce sulfur oxides, the source of sulfur is anthropogenic activities (Human activities).

So the given statement is false.

b) A flue gas scrubber removes SO2 pollution in a coal-fired power plant by using lime to convert the SO2 into alcohols:

False

The lime reacts with sulfur dioxide to give carbon dioxide and calcium sulfite.

$CaCO_{3}+SO_{2}--->CaSO_{3}+CO_{2}$

c) True

c)

3 0

3 years ago

A reaction that involves the transfer of electrons from one molecule to another is referred to as

shepuryov [24]

its a redox reaction.

3 0

3 years ago

The reaction A(B) = 2B(g) has an equilibrium constant of K = 0.045. What is the equilibrium constant for the reaction B(g) =1/2A

Mamont248 [21]

Answer:

The $K_c$ for the reaction $B(g) = \frac{1}{2}A$ will be 4.69.

Explanation:

The given equation is A(B) = 2B(g)

to evaluate equilibrium constant for $B(g) = \frac{1}{2}A$

$K_c=[B]^2[A]$

= 0.045

The reverse will be $2B\leftrightharpoons A$

Then, $K_c = \frac{[A]}{[B]^2}$

= $\frac{1}{0.045}$

= $22m^{-1}$

The equilibrium constant for $B(g) = \frac{1}{2}A$ will be

$K_c = \sqrt{K_c}$

$=\sqrt{22}$

= 4.69

Therefore, $K_c$ for the reaction $B(g) = \frac{1}{2}A$ will be 4.69.

5 0

3 years ago