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mario62 [17]
3 years ago
9

Does Kinetic energy depend only on an object’s speed and velocity?

Chemistry
2 answers:
SSSSS [86.1K]3 years ago
6 0
Yes . kinetic energy mainly focuses on movement .
BaLLatris [955]3 years ago
4 0

yes         .. . . . .. . . .. ....... . ..dlnv3r;'mw,c    kc;oqc,

xkdnnd                                                                                                

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Find the density of a piece of chocolate with these measurements: 2.4 g and 5.12 mL
Dahasolnce [82]

Answer:

0.46875g/ml

Explanation:

Density(p) = m / v unit - g/ml or Kg/m^3

Given

mass = 2.4g

volume = 5.12ml

p = m / v

= 2.4g / 5.12ml

= 0.46875g/ml

5 0
2 years ago
What causes air to move towards the water from the land during the night
icang [17]

Answer:ytejdytjtyjtyjfuyjn

Explanation:

fjynrmukjmjfyu

5 0
3 years ago
What are metallic bonds?
klemol [59]
Metallic bonds are forces that holds atoms together in a marlin substance
7 0
3 years ago
Consider the molecule BF3. (a) What is the electron config- uration of an isolated B atom? (b) What is the electron con- figurat
anzhelika [568]

For the given molecule, we are asked to give-

  1. The electron configuration of an isolated B atom
  2. The electron configuration of an isolated F atom
  3. Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride
  4. valence orbitals, if any, remain unhybridized on the B atom.
  • The electron configuration of an isolated B atom:

as atomic number of B is 5

electronic configuration will be [He] 2s² 2p¹

  • The electron configuration of an isolated F atom:

as atomic number of F is 9

electronic configuration will be  [He] 2s² 2p5

  • Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride will be sp2.

as the one s and two of p orbital from the valance shell will hybridised to make 3 hybrid orbital of B resulting in 3 B-F bonds.

  • valence orbitals, if any, remain unhybridized on the B atom will be 1

To know more about hybrisisation:

brainly.com/question/23038117

#SPJ4

8 0
1 year ago
Calculate the solubility of benzene in water at 25 c in ppm. the required henry's law constant is 5.6 bar/mol/kg and benzene's s
kap26 [50]

The relationship between pressure and solubility of the gas is given by Henry's law as:

S_g = kP_g

where,

S_g is the solubility of the gas.

k is proportionality constant i.e. Henry's constant.

P_g is pressure of the gas.

k = 5.6 bar/mol/kg (given)

P_g = 0.13 bar (given)

Substituting the values,

S_g = 5.6 bar/mol/kg\times 0.13 bar = 0.728 mole/kg

To convert mole/kg to g/kg:

Molar mass of benzene, C_6H_6 = 6\times 12+6\times 1 = 78 g/mol

0.728\times 78 = 56.784 g/kg

Now for converting into ppm:

Since, 1 ppm = 0.001 g/kg

So, 56.784\times 1000 = 56784 ppm.

Hence, the solubility of benzene in water at 25^{o} C in ppm is 56784 ppm.


7 0
3 years ago
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