Answer:
A
Step-by-step explanation:
since it says its fourteen hundredths of a meter long just move the decimal three times from 14 thus it would be 0.14
Answer:
![n = 144m^2 - 1](https://tex.z-dn.net/?f=n%20%3D%20144m%5E2%20-%201)
Step-by-step explanation:
<u>__________________________________________________________</u>
<u>FACTS TO KNOW BEFORE SOLVING :-</u>
- Let x be a number. ⇒
can also be written as
.
- To make any variable the subject of any formula , we need to isolate it.
<u>__________________________________________________________</u>
According to the question ,
![3m = \frac{(n + 1)^{\frac{1}{2} }}{4}](https://tex.z-dn.net/?f=3m%20%3D%20%5Cfrac%7B%28n%20%2B%201%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%7D%7B4%7D)
Lets multiply both the sides by 4.
![=> \frac{(n + 1)^{\frac{1}{2} }}{4} \times 4 = 3m \times 4](https://tex.z-dn.net/?f=%3D%3E%20%5Cfrac%7B%28n%20%2B%201%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%7D%7B4%7D%20%5Ctimes%204%20%3D%203m%20%5Ctimes%204)
![=> (n + 1)^{\frac{1}{2} } = 12m](https://tex.z-dn.net/?f=%3D%3E%20%28n%20%2B%201%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%20%3D%2012m)
It can be also written as :-
![=> \sqrt{(n + 1)} = 12m](https://tex.z-dn.net/?f=%3D%3E%20%5Csqrt%7B%28n%20%2B%201%29%7D%20%3D%2012m)
Lets square both the sides.
![=> [\sqrt{(n + 1)} ]^{2} = (12m)^{2}](https://tex.z-dn.net/?f=%3D%3E%20%5B%5Csqrt%7B%28n%20%2B%201%29%7D%20%5D%5E%7B2%7D%20%3D%20%2812m%29%5E%7B2%7D)
![=> n + 1 =144m^2](https://tex.z-dn.net/?f=%3D%3E%20n%20%2B%201%20%3D144m%5E2)
![=> n = 144m^2 - 1](https://tex.z-dn.net/?f=%3D%3E%20n%20%3D%20144m%5E2%20-%201)
The area of an exercise aid that is textured from the information regarding Fiona is 50 inches².
<h3>How to calculate the area?</h3>
From the information given, the measures or the exercise aid is approximately 25 inches around its base. Therefore, the radius will be calculated thus:
2πr = 25
(2 × 3.142 × r) = 25
6.284r = 25
r = 25/6.284
r = 3.978 = 4
Therefore, the area will be:
= πr²
= 3.142 × 4²
= 50 inches²
Learn more about area on:
brainly.com/question/25292086
#SPJ1
Answer:
For this case if the two events described are independent we need to satisfy:
1) ![P(shower-gel | scented) =0.42](https://tex.z-dn.net/?f=P%28shower-gel%20%7C%20scented%29%20%3D0.42)
Since by definition of independence the event shower gel is not dependent of the event scented
We also need to have that:
![P(scented |shower- gel) = P(scented)](https://tex.z-dn.net/?f=%20P%28scented%20%7Cshower-%20gel%29%20%3D%20P%28scented%29)
And the second condition that we need to satisfy is :
2) ![P(shower-gel \cap scented) = P(shower-gel) *P(scented)](https://tex.z-dn.net/?f=%20P%28shower-gel%20%5Ccap%20scented%29%20%3D%20P%28shower-gel%29%20%2AP%28scented%29)
The product of the individual probabilities represent the intersection of the two events
If we satisfy the conditions described above then we can consider the events "shower gel" and "scented" as independent events.
Step-by-step explanation:
For this case if the two events described are independent we need to satisfy:
1) ![P(shower-gel | scented) =0.42](https://tex.z-dn.net/?f=P%28shower-gel%20%7C%20scented%29%20%3D0.42)
Since by definition of independence the event shower gel is not dependent of the event scented
We also need to have that:
![P(scented |shower- gel) = P(scented)](https://tex.z-dn.net/?f=%20P%28scented%20%7Cshower-%20gel%29%20%3D%20P%28scented%29)
And the second condition that we need to satisfy is :
2) ![P(shower-gel \cap scented) = P(shower-gel) *P(scented)](https://tex.z-dn.net/?f=%20P%28shower-gel%20%5Ccap%20scented%29%20%3D%20P%28shower-gel%29%20%2AP%28scented%29)
The product of the individual probabilities represent the intersection of the two events
If we satisfy the conditions described above then we can consider the events "shower gel" and "scented" as independent events.
Answer:
650
Step-by-step explanation:
brainliest please