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Dafna11 [192]
3 years ago
15

Relationships in Figures

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
4 0

Answer:

A. 8.737

Step-by-step explanation:

I calculated it logically

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Answer is 0.696

Step-by-step explanation:

The sum number of sets possible for no two students to have the same birthday in a class of 30 is:

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Now, the probability that two students would have their birthdays on the same equal date would be:

1-0.303 = 0.696 or 70%

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